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Lady bird [3.3K]
3 years ago
7

A company settles a long-term note payable plus interest by paying $68,000 cash toward the principal amount and Page 565 $5,440

cash for interest. The amount reported as a use of cash under cash flows from financing activities is _________.
Business
1 answer:
Juli2301 [7.4K]3 years ago
7 0

Answer:

$68,000

Explanation:

The long-term note payable is a debt that is formally established through a written agreement. An example of long-term note payable is a bank loan.

When the principal and the interests of a long-term note are paid, they represent Cash outflows from the business and are recorded in the Cashflow Statement. However, their treatments are different. Another way to put it is that they bring a reduction in the cash of the organisation.

The $68,000 principal amount paid is an outflow from the company that is recorded in the financing activity section of the Cash Flow Statement

The Interest of $5,440 is also an outflow from the business but it is reported in the operating activity section of the Cash Flow Statement. The reason for its report is that it is actually reported in the Organisation's Statement of Income as an expense for the year. It, therefore, qualifies as an operating activity expense or outflow.

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You are considering opening a new plant.
kotykmax [81]

Answer:

1. $275 million

Yes

2. 30%

Explanation:

Calculation for the NPV of the investment opportunity

NPV = –100 + 30/0.08

NPV= $275 million

Therefore the NPV will be $275 million

Yes, Based on the above Calculation they should make the investment

2. Calculation for IRR

IRR: 0 = –100 + 30/IRR

Hence,

IRR = 30/100

IRR = 30%

Therefore the IRR will be 30%

The IRR is great only in a situation where the cost of capital does not go beyond 30%.

6 0
2 years ago
Gross Corporation adopted the dollar-value LIFO method of inventory valuation on December 31, 2013. Its inventory at that date w
Murrr4er [49]

Answer: $603,500

Explanation:

Ending inventory in 2014;

= Ending inventory balance 2013 + ((\frac{Inventory current price 2014}{Price index 2014} * 100) - ending inventory 2013)) * Price index 2014/100

= 550,000 + ((\frac{642,000}{107}* 100) - 550,000)) * 107/100

= $603,500

3 0
2 years ago
An oil refinery is located on the north bank of a straight river that is 3km wide. A pipeline is to be constructed from the refi
Mariulka [41]

Answer:

$6,598,076.21

Explanation:

<h2>THE KEY IS TO FIND OUT THE COST FUNCTION, the calculations are very easy!!!</h2><h2></h2><h3>In order to find the cost function, take a look at the drawing attached. </h3>

We can see the river (sort of) that is 3 km wide and the storage tanks on the other side of the river 8 km apart.

<h3 />

Laying pipes under (across) the river costs 1,000,000 the km & laying pipes over land costs 500,000 per km.

<h3 /><h3>So basically the cost function is 1,000,000 multiplied by something plus 500,000 multiplied by another something.</h3><h3 />

The distance across the river can be found by using Pythagoras Theorem. A side is 3 km the other is unknown, so we call it X. And it is equal to:

\sqrt{3^{2} +x^{2}}=\\\sqrt{9 +x^{2}}

And we multiply it by 1,000,000; the cost of laying pipe under the river, the we get:

1000000\sqrt{9+x^{2}

The distance over the land is (8-x), as we can see in the drawing. So we multiply it by its cost, 500,000. And we get 500,000(8-x).

So the cost function f(x) would be:

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)

<h2>From here, we just have to differentiate and the derivative found must be equal to zero in order to minimize cost. </h2><h3>The value of x when the derivative is zero is plugged in the original function to get the cost.</h3><h3 /><h2>LET'S DO THIS</h2>

f(x)=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(x)=1000000(9+x^{2})^{1/2}+4000000-500000x\\f'(x)=\frac{1}{2} 1000000(9+x^{2})^{-1/2}(2x)-500000\\\\f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000

<h2>f'(x)=0</h2>

f'(x)=\frac{1000000x}{\sqrt{9+x^2}}  - 500000=0\\\frac{1000000x}{\sqrt{9+x^2}}  = 500000\\\frac{2x}{\sqrt{9+x^2}}  = 1\\2x={\sqrt{9+x^2}}\\4x^2=9+x^2\\3x^2=9\\x^2=3\\x=\sqrt{3} \\

And we plug square root of 3 in the original cost function  ad we get

f(\sqrt{3} )=1000000\sqrt{9+x^{2}} + 500000(8-x)\\f(\sqrt{3})=1000000\sqrt{9+(\sqrt{3} )^{2}} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{9+3} + 500000(8-(\sqrt{3}))\\f(\sqrt{3})=1000000\sqrt{12}+500000(6.27)\\f(\sqrt{3})=1000000(3.46)+500000(6.27)\\f(\sqrt{3})=3464101.62+3133974.60\\f(\sqrt{3})=6598076.21\\

<h2>so the minimal cost is $6,598,076.21</h2><h2 /><h3 />

6 0
3 years ago
In 2019, Pine Corporation had losses of $20,000 from operations. It received $180,000 in dividends from a 25%-owned domestic cor
zubka84 [21]

Answer:

Consider the following calculations

Explanation:

Net income per books   $65,000

Add back:

Federal income taxes     9,700

Excess contributions       3,000

Life insurance premiums 10,000

$87,700

Subtract:

Tax-exempt interest       (1,500)

Excess depreciation       (4,500)

Taxable income                         $81,700

Dividend received deduction = 160000 x 80% = 128000 (full DRD doesn't create loss).

DRD will be 80% of taxable inome because percent partnership is 25% which is between 20 to 80%.

7 0
3 years ago
Ellie's Deli offers good sandwiches and fast service to its lunchtime customers from a nearby university. It also delivers the s
topjm [15]

Answer:

occasion

Explanation:

Occasion segmentation refers to dividing your potential market into target groups based on different occasions that they might purchase your products. This segmentation technique is used when target groups are defined based on specific times that they can access or purchase your products.

In this case, the same products are offered to different target groups depending on when they will be available. Ellie sells fast food to university students during lunchtime (form Monday to Friday) and offers those same products but with a different packaging to its catering clients for special events.

3 0
3 years ago
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