The function f(x) is to be graphed on a coordinate plane
2 answers:
<h2>Answer:</h2>
The point where the open circle can be drawn on the graph of the function f(x) is:
(0,0)
<h2>Step-by-step explanation:</h2>The function f(x) is given by:
f(x)= -x when x < 0
and 1 when x ≥ 0
The graph of the function f(x) is a line with a negative slope in the region x<0
and is a straight line parallel to the x-axis in the region x ≥ 0.
We know that in a graph of the function f(x) the open circle is drawn at the point where the inequality is strict i.e. that x is close to some value but could not be equal to that value.
Here x < 0
This means that x is close to zero but does not take the value 0.
Also, when x is close to zero then f(x)= -0=0
Hence, the open circle is at (0,0)
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Answer:
The right answer is:
Option OB: f(1) = -9
Common difference: 7
Step-by-step explanation:
Given sequence is:
-9, -2, 5, 12,...
Here the first number is f(1)
Common Difference:
Common difference is the difference between consecutive terms of an arithmetic sequence. It is denoted by d.
In the given sequence,
f(1) = -9
f(2) = -2
f(3) = 5
Hence,
The right answer is:
Option OB: f(1) = -9
Common difference: 7