Answer: Choice C) $1.20
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Work Shown:
Define the following events:
A = event of winning the motorcycle (valued at $9000)
B = event of winning $2000
C = event of winning $1000
D = event of winning nothing ($0)
The probability for each event is...
P(A) = 1/10000 = 0.0001
P(B) = 1/10000 = 0.0001
P(C) = 1/10000 = 0.0001
P(D) = 1 - (P(A)+P(B)+P(C))
P(D) = 1 - (0.0001+0.0001+0.0001)
P(D) = 0.9997
Or another way to see this is that there are 10000-3 = 9997 tickets that don't win anything so 9997/10000 = 0.9997
The net value for each event is
V(A) = 9000
V(B) = 2000
V(C) = 1000
V(D) = 0
Multiply the probabilities and the net values
P(A)*V(A) = 0.0001*9000 = 0.9
P(B)*V(B) = 0.0001*2000 = 0.2
P(C)*V(C) = 0.0001*1000 = 0.1
P(D)*V(D) = 0.9997*0 = 0
Then add up the results: 0.9+0.2+0.1+0 = 1.20
The expected value is 1.20
So that's why the answer is choice C
Note: this is assuming that the ticket cost $0 (or that a friend bought the ticket to be given as a gift to you)
Another note: if the ticket costs $1.20, then this is a fair game. Anything more, and the game would be unfair in favor of the house.
40 times on purple and 40 times on orange. if you divide 200 by 5, it is 40. this means 40 times it will land on each color.
Answer:
Step-by-step explanation:
9514 1404 393
Answer:
36
Step-by-step explanation:
Let n represent the number of stickers Ms Galinia has. Then the number of students is ...
(n -12)/3 . . . for first distribution of stickers*
(n +4)/5 . . . for the second distribution of stickers
Since the number of students has not changed, we can equate these values:
(n -12)/3 = (n +4)/5
5(n -12) = 3(n +4)
5n -60 = 3n +12
2n = 72
n = 36
Ms Galinia has 36 stickers.
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* If Ms Galinia has 12 left over after giving 3 to each student, then subtracting 12 from her number of stickers will give a number that is 3 times the number of students. Dividing (n-12) by 3 will give the number of students. Similar reasoning can be used for the 5-per student distribution.
One could write equations using a variable for the number of students, or variables for both students and stickers. Since we only need to know the number of stickers, it seemed reasonable to use one variable for that.