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ozzi
3 years ago
12

Sarah rolls 2 fair dice and adds the results from each. Work out the probability of getting a total more than 2.

Mathematics
2 answers:
aleksandr82 [10.1K]3 years ago
6 0

Answer:

35/36

There are total of 36 outcomes.

stira [4]3 years ago
6 0

Answer:

35/36

Step-by-step explanation:

total less than or equal to 2:

1+1

one option out of 6*6= 36

Probability of getting a total of 2: 1/6*1/6= 1/36

Probability of getting a total more than 2: 1-1/36= 35/36

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One example, take the conversion fact that there are 5 miles for every 8 km.

Now if we want to work out how many kilometres in 6 miles, the conversion above is not going to help straight away.

We first need to find how many kilometres in ONE mile [which is the unit rate]

5 miles = 8 kilometres
1 mile = 8/5 kilometres
1 mile = 1.6 kilometres

Once we know the unit rate, we can then work out the number of kilometres for any number of miles.

For example:
6 miles = 6×1.6 = 9.6 kilometres
25.5 miles = 25.5 × 1.6 = 40.8 kilometres
4 0
3 years ago
If mr. Brown and his son together had 220 dollars, and mr. Brown had 10 times as much as his son how much money did each have?
faltersainse [42]

Answer:

the son had $20 and the father had $200

Step-by-step explanation:

20 x 10 = 200

200 + 20 = 220

4 0
3 years ago
Read 2 more answers
Find the complex zeros of the following polynomial function.
GalinKa [24]

Answer:

x=\frac{-1\pm\sqrt{3}i}{2}

Step-by-step explanation:

f(x)=x^3-1

0=x^3-1

0=(x^2+2x+1)(x-1)

x-1=0

x=1 <-- Real Solution

x^2+x+1=0

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

x=\frac{-2\pm\sqrt{2^2-4(1)(1)}}{2(1)}

x=\frac{-1\pm\sqrt{1^2-4(1)(1)}}{2(1)}

x=\frac{-1\pm\sqrt{1-4}}{2}

x=\frac{-1\pm\sqrt{-3}}{2}

x=\frac{-1\pm\sqrt{3}i}{2} <-- Complex Solutions

6 0
2 years ago
Some please help I’ll give you Brainliest
Allisa [31]

Answer: line N

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The line N splits <u>XY</u> into two parts

5x+8=9x+12

-9x on each side

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-8 on each side

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divide by -4 on each side

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8 0
3 years ago
Alice has $90 to spend on
nlexa [21]

Answer:

5

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5 0
3 years ago
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