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max2010maxim [7]
3 years ago
14

Century Go...

Mathematics
1 answer:
LekaFEV [45]3 years ago
3 0

6 bills in the deposit were $10 bills.

<u>Step-by-step explanation:</u>

The total number of bills he gave the teller = 24 bills

x + y = 24 ------------(1)

Let,

x be the number of $5 bills.

y be the number of $10 bills.

The total bank deposit made using $5 and $10 bills are $150.

<u>He deposits $5 bills and $10 bills. So, the equation can be framed as : </u>

5x + 10y = 150 --------(2)

The question is asked for how many $10 bills were in the deposit,

Here 'y' is the number of $10 bills.

<u>To solve for y value : </u>

The eq(1) must be multiplied by 5 and subtract eq(2) from eq(1),

 5x + 5y = 120

-(<u>5x + 10y = 150</u>)

 <u>-5y = -30      </u>

⇒ y = 30/5

⇒ y = 6

Therefore, there were 6 bills in the deposit that are $10 bills.

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Answer:

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Step-by-step explanation:

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Let Pr(R) be the probability of picking red marbles

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Pr(R) = 8/ (8+y)

Pr(W) = 7/(7+y)

Pr(RR) = Pr(R1) * Pr( R2)

= 8/(8+y) * 7/(7+y)

Pr(RW) = Pr(R1) * Pr(W2) + Pr(W1) * Pr(R2)

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The probability of having 2 red is greater than one marble of each color.

Pr(RR) > Pr( RW)

8/(8+y) * 7/(7+y) > 2[8/(8+y) * y/(7+y)]

7/(7+y) > 2(y/(7+y)

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nalin [4]
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