Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price

Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.
Divide both the numerator and denominator by the GCD so it’s 12/1
Answer:
<u>infinitely many solutions</u>
Step-by-step explanation:
The system of equations :
- 3x + 2y = 7
- -4.5x - 3y = -10.5
Multiplying Equation 1 times 3 and Equation 2 times 2 :
- 9x + 6y = 21
- -9x - 6y = -21
Putting the equations in standard form after simplifying :
- 6y = -9x + 21 ⇒ <u>y = -1.5x + 3.5</u>
- -6y = 9x - 21 ⇒ <u>y = -1.5x + 3.5</u>
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As both equations are the same, the system will have <u>infinitely many solutions</u>.
20 x 3/4 =
20/1 x 3/4= turn the 20 into a fraction
20 x 3 / 1 x 4
60/4 =
15
The answer is 15. :)