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3 years ago

I need help with this

Mathematics

1 answer:

Anestetic [448]3 years ago

7 0

Answer:

5 prime tier

Step-by-step explanation:

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Find the lateral surface area of the triangular prism.

Aleks [24]

Answer:

is it A?

Step-by-step explanation:

I think it's A because no one has answered!

3 0

3 years ago

Write the polynomial equation for -1/5,-1/2,-4

ycow [4]

Answer:

(5x+1)(2x+1)(x+4)

Step-by-step explanation:

The factored from of a polynomial can be found from the zeros or x-intercepts of the graph.

The x-intercepts here are x= -1/5, x=-1/2 and x= -4. You can find the factors by finding the expression which solves for each value.

Since x = -1/5 then the factor is 5x+1.

Since x = -1/2 then the factor is 2x+1.

Since x = -4 then the factor is x+4.

So the factored form is (5x+1)(2x+1)(x+4).

5 0

3 years ago

Thank you!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

stiks02 [169]

Answer:

your welcomeeeeee!!!

7 0

3 years ago

Read 2 more answers

Without solving, determine the number of real solutions for each quadratic equation.

masha68 [24]

Answer:

1. x^2 − 4x + 3 = 0

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

Step-by-step explanation:

1. x^2 − 4x + 3 = 0

We need to compare this function with the general equation for a quadratic formula given by:

$f(x) = ax^2 + bx + c$

On this case we see that a=1, b = -4 and c =3

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-4)^2 -4(1)*(3)= 4 >0$ So we have two real solutions

2. 2n^2 + 7 = −4n + 5

We can rewrite the expression like this:

$2n^2 +4n +2$

On this case we see that a=2, b = 4 and c =2

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (4)^2 -4(2)*(2)= 0$ So we just one real solution

3. x − 3x^2 = 5 + 2x − x^2

We can rewrite the expression like this:

$2x^2 +x +5$

On this case we see that a=2, b = 1 and c =5

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (1)^2 -4(2)*(5)= -19$ No real solutions

4. 4x + 7 = x^2 − 5x + 1

We can rewrite the expression like this:

$x^2 -9x -6$

On this case we see that a=1, b = -9 and c =-6

We can find the discriminat with the following formula:

$\sqrt{b^2 -4ac}$

$b^2 -4ac = (-9)^2 -4(1)*(-6)= 105 >0$ So we have two real solutions

8 0

4 years ago

C. For which values of x is it true that x - 3> -2?

goblinko [34]

Answer:

x > 1, meaning anything greater than 1

Step-by-step explanation:

solve for x

move the 3 to the right to leave the x by itself

x - 3 + 3 > -2 + 3

x > 1

6 0

3 years ago

Read 2 more answers