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Art [367]
3 years ago
9

-11=-6+p/4 (liberal arts mathematics)

Mathematics
2 answers:
8_murik_8 [283]3 years ago
6 0
The answer is p= -20
trasher [3.6K]3 years ago
5 0

First you have to get rid of the fraction, so you multiply by 4.

-11=-6+p/4

Then you get -44=-24+p. Next you get P by itself, so you add 24 on both sides and that cancels out the -24 on the right.

-20=P Your final answer should have been B.

I hope that helped

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There are 96000 males and 80000 females in a town. find ratio of males to the total population​
UkoKoshka [18]

Answer:

6:5

Step-by-step explanation:

GIven data

Number of males population= 96000

Number of females population= 80000

Required

The ratio of male to the female population

We can start by expressing the ratio as a fraction, we have

=96000/80000

Let us further reduce

=96/80

=6/5

Hence the ratio is 6:5

3 0
3 years ago
If f(x) = x^3 – 2x^2 – 29x + 30 and f(6) = 0, then find all of the zeros of f(x)
saw5 [17]

Answer:

1, 6, and -5

make it 0

8 0
2 years ago
The perimeter of a park is 300 feet the length of the park is 50 feet longer than the width. Find the length
arlik [135]

Answer:

55.41 feet

Step-by-step explanation:

Let the width be x.

ATQ, (x+50)*x=300, x=5*srt(37)-25=5.41. Length is 55.41 feet

8 0
3 years ago
Find the critical points of the function and use the First Derivative Test to determine whether the critical point is a local mi
Andre45 [30]

Answer:

Critical points are 1 and -1

Maximum at x=1

Minimum at x=-1

Step-by-step explanation:

We are given that a function

f(x)=3tan^{-1}(x)-\frac{3}{2} x+5 on (-\infty,\infty)

We have to find the critical points of the function.

To find the critical point we will differentiate function w.r.t x and then substitute f'(x)=0

f'(x)=\frac{3}{1+x^2}-\frac{3}{2}

\frac{d(tan^{-1}x)}{dx}=\frac{1}{1+x^2}

f'(x)=0

\frac{3}{1+x^2}-\frac{3}{2}=0

\frac{3}{1+x^2}=\frac{3}{2}

1+x^2=2

x^2=2-1=1

x=\pm1

Therefore, the critical points of the given function are 1 and -1.

f(0)=3-\frac{3}{2}=\frac{3}{2}

f'(1)=0

f'(2)=\frac{3}{5}-\frac{3}{2}=-\frac{9}{10}

When we goes from 0 to 2 then the sign of derivative  change from positive to negative .Therefore, function has local maximum at x=1.

f(-2)=\frac{3}{5}-\frac{3}{2}=-\frac{9}{10}

f(-1)=0

f(0)=\frac{3}{2}

When we goes form -2 to 0 then the sign of derivative change from negative to positive .Hence , function has local minimum at x=-1

Hence, critical points are local maximum and local minimum .

3 0
3 years ago
I need the real answer for this one please!?
Vera_Pavlovna [14]

Answer:

x=7

Step-by-step explanation:

inverse problems

48+1=49

the root of 49 is 7

4 0
3 years ago
Read 2 more answers
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