Answer:
23
Step-by-step explanation:
Considering the situation described, we have that:
a) The critical value is of z = -1.645.
b) Since the test statistic is less than the critical value, we should reject the null hypothesis H0.
<h3>What is the critical value?</h3>
We have a left-tailed test, as we are testing if the proportion is less than a value. Hence the critical value is z with a p-value equals to the significance level, hence z with a p-value of 0.05, hence z = -1.645.
<h3>What is the decision?</h3>
Considering the test statistic, for a left-tailed test, we have that:
- Less than the critical value: Reject H0.
- Equal or greater: Do not reject.
In this problem, z = -2.39 is less than -1.645, hence we should reject the null hypothesis H0.
More can be learned about the test of an hypothesis at brainly.com/question/13873630
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Log3 (x) + 4125=3 final answer
The rate at which the water from the container is being drained is 24 inches per second.
Given radius of right circular cone 4 inches .height being 5 inches, height of water is 2 inches and rate at which surface area is falling is 2 inches per second.
Looking at the image we can use similar triangle propert to derive the relationship:
r/R=h/H
where dh/dt=2.
Thus r/5=2/5
r=2 inches
Now from r/R=h/H
we have to write with initial values of cone and differentiate:
r/5=h/5
5r=5h
differentiating with respect to t
5 dr/dt=5 dh/dt
dh/dt is given as 2
5 dr/dt=5*-2
dr/dt=-2
Volume of cone is 1/3 π![r^{2} h](https://tex.z-dn.net/?f=r%5E%7B2%7D%20h)
We can find the rate at which the water is to be drained by using partial differentiation on the volume equation.
Thus
dv/dt=1/3 π(2rh*dr/dt)+(
*dh/dt)
Putting the values which are given and calculated we get
dv/dt=1/3π(2*2*2*2)+(4*2)
=1/3*3.14*(16+8)
=3.14*24/3.14
=24 inches per second
Hence the rate at which the water is drained from the container is 24 inches per second.
Learn more about differentaiation at brainly.com/question/954654
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