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BartSMP [9]
3 years ago
7

7 less than two times the sum of 6 and a

Mathematics
1 answer:
Sophie [7]3 years ago
3 0

Answer:

(2(6+a))-7

That is your answer!

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if my grade is 69% what will my grade be if i got a 3.3 of 4 on a essay and it's worth 25% of my grade?​
juin [17]

Answer:

72.4%

Step-by-step explanation:

The essay is 25% of your grade, and the rest is 75% of your grade.

25 (3.3/4) + 75 (0.69) ≈ 72.4

6 0
3 years ago
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
I need help with #4<br> anyone pls?
kvasek [131]

Answer:

C. 0 6 10

Step-by-Step-Explanation:

the number on the left of the indicated operation is the original set

the number '2' next to R shows that you need to multiply certain numbers by 2

the subscript on the R's shows which row the multiplication needs to be done on...

so in this case, leave the second row alone: 1  3  4

but multiply the first row by 2: 0  6  10

5 0
3 years ago
Cuantos paquetes de 10 vasos ocupo para empacar 1367 vasos
SpyIntel [72]
137 paquetes de vasos, aunque el último nomas contiene 7 vasos se necesita el paquete para que no queden sin empacar
8 0
3 years ago
Example 3:
Darina [25.2K]
You can just use a calculator but when you add the numbers all together you get 323
6 0
2 years ago
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