Answer:
C). 0.83193
Step-by-step explanation:
There are total of 90 passengers of which 27 are for business.
The probability of passengers for business = 27/90
The probability of passengers for business p = 0.3
The probability of passengers not for business q = 1-The probability of passengers for business
= 1-0.3
= 0.7
Random sample of 5 passenger, probability of at least one business passenger = 1 - probability of no business passenger
probability of no business passenger
= 5C0(0.3)^0 * (0.7)^5
= 1 *1*0.16807
= 0.16807
probability of at least one business passenger = 1 - probability of no business passenger
= 1-0.16807
=0.83193
That would depend on the size of your classroom. but, typically the answer is no
Answer:25 m
Step-by-step explanation:
