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gizmo_the_mogwai [7]
3 years ago
15

You plan to put anti-theft devices on each garment in your store. You have 1,320 garments, and it takes an employee 20 seconds t

o tag a garment. How long will it take TWO employees to tag all the garments?
Mathematics
2 answers:
makvit [3.9K]3 years ago
6 0

Answer:

3 hours 40 minutes.

Step-by-step explanation:

We are told that we have 1320 garments and it takes an employee 20 seconds to tag a garment.

1 employee tags one garment in 20 seconds.

So garments tagged by 1 employees in 1 minute will be \frac{60}{20} =3 garments.

2 employees will tag 3*2=6 garments in 1 minute.

To find the total time it will take two employees to tag all the garments we will divide total number of garments by 6.

\text{Time taken by two employees to tag 1320 garments}=\frac{1320}{6}

\text{Time taken by two employees to tag 1320 garments}=220

Therefore, it will take 220 minutes or 3 hours and 40 minutes for 2 employees to tag 1320 garments.

Sergeu [11.5K]3 years ago
5 0

Answer:

13,200 Seconds, or 220 Minutes


Step-by-step explanation:

<u>Since there are 2 employees working at the same time, so in 20 seconds, they will be tagging a total of 2 garments. So we can say the rate is:</u>

rate = \frac{20 Seconds}{2 Garments}


So how long would it take to tag 1320 garments?

<em>We set up the ratio, cross multiply, and solve.</em>

\frac{TimeInSeconds}{NumberOfGarments}=\frac{20}{2}=\frac{x}{1320}}\\\frac{20}{2}=\frac{x}{1320}\\20*1320=2x\\x=\frac{26400}{2}=13,200 seconds


Or in minutes, we divide by 60, so we have:

\frac{13,200}{60}=220 Minutes

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If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen
alexandr1967 [171]

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: 2(-4y-9)+5y=-6

Step-by-step explanation:

We will solve the initial steps for substitution method for finding the correct answer

Given equations are:

x+4y = -9\ \  \ \ Eqn1\\2x+5y=-6\ \ \ Eqn2

From equation one

x+4y = -9\\x+4y-4y = -9-4y\\x = -4y-9

Putting x = -4y-9 in equation 2

2(-4y-9)+5y=-6

Hence,

The new equation after the expression equivalent to x from the first equation is substituted into the second equation is: 2(-4y-9)+5y=-6

Keywords: Linear equations, variables

Learn more about linear equations at:

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#LearnwithBrainly

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mr and mrs gracia took their three children to see a matinee on saturday. they spent a total of 55.50, which included 29.95 at t
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Step-by-step explanation:

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I need to know the improper fractions answers for:
zmey [24]

Answer:

Part 1) x=\frac{15}{2}\ units

Part 2) z=\frac{15\sqrt{3}}{2}\ units

Part 3) y= \frac{15\sqrt{3}}{4}\ units

Part 4) b= \frac{45}{4}\ units

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

cos(60^o)=\frac{x}{15} ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

cos(60^o)=\frac{1}{2}

substitute

\frac{1}{2}=\frac{x}{15}

solve for x

x=\frac{15}{2}\ units ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

15^2=x^2+z^2

substitute the value of x

15^2=(\frac{15}{2})^2+z^2

solve for z

z^2=15^2-(\frac{15}{2})^2

z^2=225-\frac{225}{4}

z^2=\frac{675}{4}

z=\frac{\sqrt{675}}{2}\ units

simplify

z=\frac{15\sqrt{3}}{2}\ units

step 3

Find the value of y

In the right triangle of the right

sin(30^o)=\frac{y}{z} ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

sin(30^o)=\frac{1}{2}

so

\frac{1}{2}=y:\frac{15\sqrt{3}}{2}

solve for y

\frac{1}{2}= \frac{2y}{15\sqrt{3}}

y= \frac{15\sqrt{3}}{4}\ units

step 4

Find the value of b

In the right triangle of the right

cos(30^o)=\frac{b}{z} ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

cos(30^o)=\frac{\sqrt{3}}{2}

so

\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}

solve for y

\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}

b= \frac{45}{4}\ units

7 0
3 years ago
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