A set of data has 12 pieces of data. Which of the following statements is NOT TRUE?

1 answer:

5 0

To help you understand this, it is helpful to create a sample set of data:

__,__,__,(Q1 is here)__,__,__,(median is here)__, __,__,(Q3is here)__,__,__

A. The first 3 lines are 3 pieces of data in the first quartile.

B. here are 6 pieces of data between the 1st and 3rd quartiles.

D. There are 3 pieces of data in the upper quartile.

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What is the volume of a rectangular prism whose dimensions are 2 feet, 2.5 feet and 4 feet?

IrinaK [193]

Answer:

It’s B, 20 cubic feet

Step-by-step explanation:

Volume is length x width x height so
2 x 2.5 x 4 is 20

4 0

2 years ago

PLEASE HELP

Dmitrij [34]

If the equation for volume is V=l*w*h, you can plug in all of the information you know. When you do this, the equation becomes 1440=15*12*h, or 1440=180*h (because 15*12=180). You can divide both sides by 180 to get h. 1440/180=8, do the depth of the pool is 8 ft. You can also check this answer by making sure that 15*12*8 is equal to 1440 (which it is). I hope this helped!

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2 years ago

140 subtracted from the square of a number the result is three times the number find the negative solution

natima [27]

Answer:

$Suppose~that~the~number~is~x.\\According~to~question,\\x^2-140=3x\\or, x^2-3x-140=0\\From~the~quadratic~formula,\\x = \frac{-(-3)+\sqrt{(-3)^2-4(1)(-140)} }{2(1)} ~and ~x= \frac{-(-3)-\sqrt{(-3)^2-4(1)(-140)} }{2(1)} \\or, x = \frac{3+\sqrt{9+560} }{2}~and~x=\frac{3-\sqrt{9+569} }{2}\\or, x = \frac{3+\sqrt{569} }{2}~and~x=\frac{3-\sqrt{569} }{2}\\So,~the~required~negative~number~is~\frac{3-\sqrt{569} }{2}.$