<span>Two trains start heading toward each other from two cities, the distance between which is 720 km, and meet right in the middle.
The second train left 1 hour after the first train, but traveled at a speed 4 km/hour faster than the first train.
Find the speed of both trains.
:
If they met half-way, each train traveled 360 mi
let s = speed of the slower train
then
(s+4) = speed of the faster train
:
Write a time equation
Slow train time - fast train time = 1 hr
- = 1
multiply equation by s(s+4), cancel the denominators</span>360(s+4) - 360s = s(s+4)<span>360s + 1440 - 360s = s^2 + 4s
A quadratic equation
0 = s^2 + 4s - 1440
Use the quadratic formula; a=1; b=4; c=-1440. but this will factor to:
(s-36)(s+40) = 0
positive solution
s = 36 mph, speed of the slow train
then obviously;
40 mph, the speed of the faster
:
:
Check this by finding the actual time of each
360/36 = 10 hrs
360/40 = 9 hrs, 1 hr less</span>
If you are finding the perimeter the answer would be:
$15.50
If you do 9*$1.75=$15.75
If you do 10*$1.75=17.50
When you find perimeter it’s length+length+ width+ width
This gives you $15.50
If you are finding the area the answer would be:
$157.50
To find area you do 10*9=90
Then, you do 90*$1.75=$157.50
(f+g)(x)=0
f (x) + g (x)=0
now,
substitute their values
x^2 -4x + x -18 = 0
x^2 -3x -18 =0
x^2 - 6x + 3x - 18 =0
x (x-6) + 3 (x-6) = 0
(x-6)(x+3) = 0
we have to find it's zeroes (or roots) now:
x-6 =0
x = 6
x +3 =0
x = -3
Answer:
The answer is
<h2>
</h2>
Step-by-step explanation:
The midpoint M of two endpoints of a line segment can be found by using the formula
<h3>
</h3>
where
(x1 , y1) and (x2 , y2) are the points
From the question the points are
A(-4, 7) and S(5,3)
The midpoint is
<h3>
</h3>
We have the final answer as
<h3>
</h3>
Hope this helps you
