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Rom4ik [11]
3 years ago
13

The truth set of x2 + x = 8

Mathematics
1 answer:
Shkiper50 [21]3 years ago
3 0

Answer:   \bold{x=\dfrac{-1+ \sqrt{33}}{2}\qquad and\qquad x=\dfrac{-1- \sqrt{33}}{2}}

<u>Step-by-step explanation:</u>

x^2+x=8\\\\\text{subtract 8 from both sides:}\\x^2+x-8=0\qquad \rightarrow \qquad a=1, b=1, c=-8\\\\\\\text{Use the quadratic formula to solve for x:}\\x = \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\\x = \dfrac{-(1)\pm \sqrt{(1)^2-4(1)(-8)}}{2(1)}\\\\\\.\ =\dfrac{-1\pm \sqrt{1+32}}{2}\\\\\\.\ =\dfrac{-1\pm \sqrt{33}}{2}\\\\\\x=\dfrac{-1+ \sqrt{33}}{2}\qquad and\qquad x=\dfrac{-1- \sqrt{33}}{2}

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