The correct answers would be a b and 2 because I don’t know this is a test to be honestly
Answer:
0.5 is part of the confidence interval, and thus, it is reasonable to believe more than half of food delivery drivers eat some of the food they are delivering.
Step-by-step explanation:
95% confidence interval for the true proportion of food delivery drivers who eat some of the food they are delivering is (0.398, 0.706).
This means that we are 95% sure that the true proportion of food delivery drivers who eat some of the food they are delivering is (0.398, 0.706).
Is it reasonable to believe more than half of food delivery drivers eat some of the food they are delivering?
0.5 is part of the confidence interval, and thus, it is reasonable to believe more than half of food delivery drivers eat some of the food they are delivering.
2 x - 3² + - 3
2 x 9 + - 3
18 - 3
15
So thi sis really simple since you have an equal sign so
(n/3)-(5n/6)=1/3
to subtract fractions, make the bottom number the same
n/3 times 2/2=2n/6
(2n/6)-(5n/6) or (2n-5n)/6 so
-3n/6=1/3
multiply both sides by 6
-3n=6/3=2
-3n=2
divide both sides by 3
-n=2/3
mmultiply boht by -1
n=-2/3
tada
n=-2/3