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Andrews [41]
3 years ago
9

Which of the following examines the organizational resource of information and regulates its definitions, uses, value, and distr

ibution ensuring it has the types of data or information required to function, and grow effectively?
A. Information code
B. Information technology
C.Information management
D. Information governance
Computers and Technology
1 answer:
hichkok12 [17]3 years ago
4 0

Answer:C)Information management

Explanation: Information management is the technique through which the organization and handling of the the data/ information takes place.This technique is made for helping the organization and their business for the supporting the function and processes.

The facilities provided by the information management system is  development, management, designing, innovation etc.

Other options are incorrect because they are used for the coding process,technology and governing of the data, hence no management activity is done by them.Thus, the correct option is option(C).

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Jax earned 144 points on a research project. In this situation, what is the number 144? Group of answer choices data information
fredd [130]

Answer: data

Explanation:

Data refers to symbols or numbers that aren't meaningful. It's an an individual unit which consists of raw materials. Data hato be interpreted in order to become meaningful. They are fact or figures. Examples of data include 24, London, 144 etc.

Information on the other hand is a data that has been processed. e.g. Bob has an aggregate score of 144. Based on the question given, the number 144 is a data as it isn't meaningful yet.

3 0
3 years ago
The FCFS algorithm is particularly troublesome for ____________.
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The correct option is (b) multiprogramming systems

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Explanation:

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3 years ago
Write a procedure named Str_find that searches for the first matching occurrence of a source string inside a target string and r
kirill115 [55]

Answer: Provided in the explanation section

Explanation:

Str_find PROTO, pTarget:PTR BYTE, pSource:PTR BYTE

.data

target BYTE "01ABAAAAAABABCC45ABC9012",0

source BYTE "AAABA",0

str1 BYTE "Source string found at position ",0

str2 BYTE " in Target string (counting from zero).",0Ah,0Ah,0Dh,0

str3 BYTE "Unable to find Source string in Target string.",0Ah,0Ah,0Dh,0

stop DWORD ?

lenTarget DWORD ?

lenSource DWORD ?

position DWORD ?

.code

main PROC

  INVOKE Str_find,ADDR target, ADDR source

  mov position,eax

  jz wasfound           ; ZF=1 indicates string found

  mov edx,OFFSET str3   ; string not found

  call WriteString

  jmp   quit

wasfound:                   ; display message

  mov edx,OFFSET str1

  call WriteString

  mov eax,position       ; write position value

  call WriteDec

  mov edx,OFFSET str2

  call WriteString

quit:

  exit

main ENDP

;--------------------------------------------------------

Str_find PROC, pTarget:PTR BYTE, ;PTR to Target string

pSource:PTR BYTE ;PTR to Source string

;

; Searches for the first matching occurrence of a source

; string inside a target string.

; Receives: pointer to the source string and a pointer

;    to the target string.

; Returns: If a match is found, ZF=1 and EAX points to

; the offset of the match in the target string.

; IF ZF=0, no match was found.

;--------------------------------------------------------

  INVOKE Str_length,pTarget   ; get length of target

  mov lenTarget,eax

  INVOKE Str_length,pSource   ; get length of source

  mov lenSource,eax

  mov edi,OFFSET target       ; point to target

  mov esi,OFFSET source       ; point to source

; Compute place in target to stop search

  mov eax,edi    ; stop = (offset target)

  add eax,lenTarget    ; + (length of target)

  sub eax,lenSource    ; - (length of source)

  inc eax    ; + 1

  mov stop,eax           ; save the stopping position

; Compare source string to current target

  cld

  mov ecx,lenSource    ; length of source string

L1:

  pushad

  repe cmpsb           ; compare all bytes

  popad

  je found           ; if found, exit now

  inc edi               ; move to next target position

  cmp edi,stop           ; has EDI reached stop position?

  jae notfound           ; yes: exit

  jmp L1               ; not: continue loop

notfound:                   ; string not found

  or eax,1           ; ZF=0 indicates failure

  jmp done

found:                   ; string found

  mov eax,edi           ; compute position in target of find

  sub eax,pTarget

  cmp eax,eax    ; ZF=1 indicates success

done:

  ret

Str_find ENDP

END main

cheers i hoped this helped !!

6 0
3 years ago
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