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Andrews [41]
4 years ago
9

Which of the following examines the organizational resource of information and regulates its definitions, uses, value, and distr

ibution ensuring it has the types of data or information required to function, and grow effectively?
A. Information code
B. Information technology
C.Information management
D. Information governance
Computers and Technology
1 answer:
hichkok12 [17]4 years ago
4 0

Answer:C)Information management

Explanation: Information management is the technique through which the organization and handling of the the data/ information takes place.This technique is made for helping the organization and their business for the supporting the function and processes.

The facilities provided by the information management system is  development, management, designing, innovation etc.

Other options are incorrect because they are used for the coding process,technology and governing of the data, hence no management activity is done by them.Thus, the correct option is option(C).

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Counting calculus students. About A university offers 3 calculus classes: Math 2A, 2B and 2C. In both parts, you are given data
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Answer:

Part (a) n(A∩B∩C) = 4

Part (b) n(A∪B∪C) = 54

Explanation:

n(A) = no. of students who took Math 2A

n(B) = no. of students who took Math 2B

n(C) = no. of students who took Math 2C

n(A∩B) = no. of students who took both Math 2A and 2B

n(A∩C) = no. of students who took both Math 2A and 2C

n(B∩C) = no. of students who took both Math 2B and 2C

n(A∩B∩C) = no. of students who took all three Math 2A, 2B and 2C

n(A∪B∪C) = no. of total students in a group

∩ represents Intersection and ∪ represents Union

Part (a)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)  

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157 = 51 + 80 + 70 - 15 - 20 - 13 + n(A∩B∩C)

Re-arranging the equation to solve for n(A∩B∩C) since we want to find out those students who took all three classes

n(A∩B∩C) = 157 - 51 - 80 - 70 + 15 + 20 + 13

n(A∩B∩C) = 4

So there are 4 students in group A who took all three classes

Part (b)

n(A∪B∪C) = n(A) + n(B) + n(C) - n(A∩B) - n(A∩C) - n(B∩C) + n(A∩B∩C)

This time we are given n(A∩B∩C) students who took all three classes and want to find n(A∪B∪C) that is total number of students

n(A∪B∪C) = 28 + 28 + 25 - 11 - 9 - 10 + 3

n(A∪B∪C) = 54

So there are total 54 students in group B

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