Main Answer:In the classic experimental design, there are two groups: the <u>treatment group and the control group.</u>
<u>Sub heading:</u>
<u>Explain treatment group and control group?</u>
Explanation:
1.The treatment group also known as the experimental group receives the treatment that the researcher is evaluating.
2.the control group on the other hand does not receive the treatment.
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Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
Answer:
The answer is D. Implement STP or RSTP.
Explanation:
STP (Spanning Tree Protocol) was built to serve as a remedy for network issues. Existing before switches were developed, it works as a substitute for a switch when a switch is wired incorrectly (as seen in the question) or when it fails. STP has two roles:
- To serve as an alternative when there is network failure or changes.
- To block out issues caused by loops on a network
RSTP (Rapid Spanning Tree Protocol) was built to optimize the standard STP. When there is a topology change, spanning tree convergence is much faster than the standard STP.
To prevent network failure in the future, STP or RSTP should be implemented.
I would say the statement given above is true. <span>Although a variety of different styles of documentation exist for report preparation, each style requires the same basic information. Hope this answers the question. Have a nice day.</span>
Answer:
CT = 470nF + 1000nF = 1470nF or 1.47μF
Explanation:
When capacitors are connected together in parallel the total or equivalent capacitance, CT in the circuit is equal to the sum of all the individual capacitors added together. This is because the top plate of capacitor, C1 is connected to the top plate of C2 which is connected to the top plate of C3 and so on. The same is also true of the capacitors bottom plates. Then it is the same as if the three sets of plates were touching each other and equal to one large single plate thereby increasing the effective plate area in m2.
Since capacitance, C is related to plate area ( C = ε(A/d) ) the capacitance value of the combination will also increase. Then the total capacitance value of the capacitors connected together in parallel is actually calculated by adding the plate area together. In other words, the total capacitance is equal to the sum of all the individual capacitance’s in parallel. You may have noticed that the total capacitance of parallel capacitors is found in the same way as the total resistance of series resistors.
The currents flowing through each capacitor and as we saw in the previous tutorial are related to the voltage.