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4 years ago

5\2,3 and 3\2,8 find the distance

Mathematics

1 answer:

pochemuha4 years ago

4 0

Answer:

√26 ≈ 5.1 units

Step-by-step explanation:

√(x₂ - x₁)² + (y₂ - y₁)²

√(3/2 - 5/2)² + (8 - 3)²

√(-1)² + (5)²

√1 + 25

√26

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Charra [1.4K]

Answer:

x > 1.7 minutes

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Step-by-step explanation:

The two plans must be defined by the equation of the line y = mx + b, where

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m = slope or payment of additional cents per minute

x = time expressed in minutes

For Plan A, we have

y = 4x + 40.10 (Equation A)

While plan B is defined as

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Plan A must be less than Plan B,

4x + 40.10 < 7x + 35

We put the “x” on the left side and the independent terms on the right side,

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We add algebraically,

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We multiply the equation by -1 to eliminate the two “minus” signs, changing the inequality sign,

3x > 5.10

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x > 5.10 / 3

We solve, calculating the value of x,

x > 1.7 minutes

The monthly telephone usage amounts so that plan A is not greater than plan B are all greater than 1.7 minutes.

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3 years ago

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Advocard [28]

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Step-by-step explanation:

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3 years ago

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Find the value of "c" by completing the square. h²- 16h + c

Sunny_sXe [5.5K]

Answer:

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Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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4 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

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4 years ago

5\2,3 and 3\2,8 find the distance​

5\2,3 and 3\2,8 find the distance