Answer:
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Find a point-slope form for the line that satisfies the stated conditions. Slope , passing through (-5,4)
I really need this question answered
By:
I don't see a value for the slope. We need that to set the equation, otherwise I can write an unlimited number of equations that pass through (-5,4).
I'll assume a slope so that you can see how the procedure would work. I like 6, so we'll assume a slope of 6.
The equation for a straight line has the form y = mx + b, where m is the slope and y is the y-intercept, the value of y when x = 0. We want a line that has slope 6, so:
y = 6x + b
We need to find b, so substitute the point (-5,4) that we know is on the line:
4 = 6*(-5) + b and solve for b
4 = -30 + b
b = 34
The line is y = 6x + 34
Answer:
8m^5-33m^3
Step-by-step explanation:
Combine like terms Expand and simplify
Answer:
2
n
3
+
6
n
2
+
8
n
Step-by-step explanation:
2n(n2 + 3n + 4)
<u><em>Simplify :</em></u>
= 2
n
3
+
6
n
2
+
8
n
Answer:
There is 7/15 left in the bag
Step-by-step explanation:
So, you need to find a common denominator between 3 and 5 which is 15
multiply the numerator and the denominator by 3 in 1/5. Then, multiply the numerator and the denominator by 5 in 1/3.
1/3*5=5/15
1/5*3=3/15
Add them together.
5/15+3/15=8/15
Lastly, subtract 15/15 by 8/15
15/15-8/15=7/15
