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Papessa [141]
3 years ago
9

Solve: –x – 7 = –2x – 11

Mathematics
2 answers:
Ivan3 years ago
8 0
<span>Simplifying (7 + -2x)(11 + -2x)(x) = 0 Reorder the terms for easier multiplication: x(7 + -2x)(11 + -2x) = 0 Multiply (7 + -2x) * (11 + -2x) x(7(11 + -2x) + -2x * (11 + -2x)) = 0 x((11 * 7 + -2x * 7) + -2x * (11 + -2x)) = 0 x((77 + -14x) + -2x * (11 + -2x)) = 0 x(77 + -14x + (11 * -2x + -2x * -2x)) = 0 x(77 + -14x + (-22x + 4x2)) = 0 Combine like terms: -14x + -22x = -36x x(77 + -36x + 4x2) = 0 (77 * x + -36x * x + 4x2 * x) = 0 (77x + -36x2 + 4x3) = 0 Solving 77x + -36x2 + 4x3 = 0 Solving for variable 'x'. Factor out the Greatest Common Factor (GCF), 'x'. x(77 + -36x + 4x2) = 0 Factor a trinomial. x((7 + -2x)(11 + -2x)) = 0 </span>
kumpel [21]3 years ago
8 0
-x-7=-2x-11
   +7       +7 

-x= 2x-4
+2x+2x

x=-4



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Rewrite the expression 4+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B16-%284%29%285%29%7D" id="TexFormula1" title="\sqrt{16-(4)(
Inessa05 [86]

Answer:

2+i

Step-by-step explanation:

Given the expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}

To find:

The expression of above complex number in standard form a+bi.

Solution:

First of all, learn the concept of i (pronounced as <em>iota</em>) which is used to represent the complex numbers. Especially the imaginary part of the complex number is represented by i.

Value of i =\sqrt{-1}.

Now, let us consider the given expression:

\dfrac{4+\sqrt{16-(4)(5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-(4\times 5)}}{2}\\\Rightarrow \dfrac{4+\sqrt{16-20}}{2}\\\Rightarrow \dfrac{4+\sqrt{-4}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)(4)}}{2}\\\Rightarrow \dfrac{4+\sqrt{(-1)}\sqrt4}{2}\\\Rightarrow \dfrac{4+\sqrt4i}{2} \ \ \ \ \ (\because \sqrt{-1} =i) \\\Rightarrow \dfrac{4+2i}{2}\\\Rightarrow 2+i

So, the given expression in standard form is 2+i.

Let us compare with standard form a+bi so we get a =2, b =1.

\therefore The standard form of

\dfrac{4+\sqrt{16-(4)(5)}}{2}

is: \bold{2+i}

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jeka94

Answer:

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