The 2 fractions are the possibilities
Answer:
Step-by-step explanation:
a) Denote the event of commercially availability of f_uel cell technology as F_, commercial availability of solar power technology as S
Write the probability of energy supplied by these energy sources in the next 10 years
P(energy supplied) = P(S ∪ F) -----(1)
Rewrite eqn (1)
P(energy supplied) = P(S) + P(F) - P(F) P(S) ----(2)
substitute 0.85 for P(S) and 0,7 for P(F) in eqn (2) to find the probability of energy supplied by these energy sources
P(energy supplied) = 0.85 + 0.7 - (0.7 * 0.85)
= 0.85 + 0.7 - (0.595)
= 1.55 - 0.595
= 0.955
Therefore, the probability that there will be energy supplied by these two alternative sources in the next 10 years is 0.955
B) write the probability of only one source of energy available
P(only one source of energy available) =
∪
---(3)
Rewrite the equation (3)
P(only one source of energy available) =
![=P(\bar F S)+P(\bar S F)\\\\=\{[1-P(F)]P(S)+[1-P(S)]P(F)\}---(4)](https://tex.z-dn.net/?f=%3DP%28%5Cbar%20F%20S%29%2BP%28%5Cbar%20S%20F%29%5C%5C%5C%5C%3D%5C%7B%5B1-P%28F%29%5DP%28S%29%2B%5B1-P%28S%29%5DP%28F%29%5C%7D---%284%29)
![=\{[1-0.7]0.85+[1-0.85]0.7\}\\\\=0.255+0.105\\\\=0.36](https://tex.z-dn.net/?f=%3D%5C%7B%5B1-0.7%5D0.85%2B%5B1-0.85%5D0.7%5C%7D%5C%5C%5C%5C%3D0.255%2B0.105%5C%5C%5C%5C%3D0.36)
Therefore,The probability that only one of the two alternative energy sources will be commercially viable in the next 10 years is 0.36
X ≤ 1 and x ≥ 3
Hope this helps :)
Answer:
The difference in the sample proportions is not statistically significant at 0.05 significance level.
Step-by-step explanation:
Significance level is missing, it is α=0.05
Let p(public) be the proportion of alumni of the public university who attended at least one class reunion
p(private) be the proportion of alumni of the private university who attended at least one class reunion
Hypotheses are:
: p(public) = p(private)
: p(public) ≠ p(private)
The formula for the test statistic is given as:
z=
where
- p1 is the sample proportion of public university students who attended at least one class reunion (
)
- p2 is the sample proportion of private university students who attended at least one class reunion (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the alumni from public university (1311)
- n2 is the sample size of the students from private university (1038)
Then z=
=-0.207
Since p-value of the test statistic is 0.836>0.05 we fail to reject the null hypothesis.
5/68
5 can go into 68 13 times with a remainder of 3
So we add a decimal point and a zero.
Carry the 3 and zero down making 30
5 can go into 30 6 times making the answer 13.6