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zvonat [6]
3 years ago
12

Normalize the following relation:

Computers and Technology
1 answer:
lora16 [44]3 years ago
5 0

Answer:

Hi Riahroo! This is a good question on the concept of relational databases.

We can normalize the relations as follows:

Flight

(flightnumber (unique), flighttime, airline_id, departure_city, arrival_city,  passenger_id, pilot_id, airplane_id)

has_one_and_belongs_to :airline

has_many :passengers

has_one :pilot

Itinerary(passenger_id, flight_id)

Belongs_to  

Passenger_details  

(passengername (unique), gender, date_of_birth)

has_many :flights

Pilot

(pilotname (unique), gender, date_of_birth)

has_many :flights

airline(airlinename)

airplane(planeID, type, seats))

Explanation:

To normalize a relation, we have to remove any redundancies from the relationships between database objects/tables and simplify the structure. This also means simplifying many-to-many relationships. In this question, we see there is a many-to-many relationship between flights and passengers. To resolve this we can introduce a join table which simplifies this relationship to a one-to-many between the objects.  

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...........is a systems development technique that tests system concepts and provides an opportunity to examine input, output, a
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A​ client-server application that requires nothing more than a browser is called​ ________.
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Hope this helps
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3 years ago
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5 0
3 years ago
A commonly-used estimate for the number of bytes needed to store one
Basile [38]

Answer:

0.127 miles ; 5.458 *10^8 miles

Explanation:

Number of bytes needed to store a page = 2000

Number of pages (Harry Potter's book) = 800

Total memory required to store entire book = (2000 * 800) = 1600000 = 16 * 10^5 bytes

Hence,

1 byte of memory will store : (height of each book / memory size of each book)

= 3 ÷ 16 * 10^5

= 1.875 * 10^-6

For 32 bit memory space :

(1.875 * 10^-6 * 2^32) = 8053.06368 inches

1 inch = 1.578 * 10^-5 mile

8053.06368 inches = 8053.06368 * (1.578 * 10^-5) = 0.1270773448704 miles

= 0.127 miles

For 64 bit memory size :

(1.875 * 10^-6 * (2^64)) = 3.45876 * 10^13 inches

(3.45876 * 10^13) * (1.578 * 10^-5)

= 5.458 *10^8 miles

3 0
2 years ago
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