Answer:
0=0
infinitely many solutions
Step-by-step explanation:
plug x=2y+3 as x into 3x-6y=9...so
3(2y+3)-6y=9, which has our x=2y+3 plugged in because that is what x equals
if you solve its
6y+9-6y=9
0y=0
y=0
making it 0=0
you can't go further from this
1. To solve this exercise, you must make a system of equations.
2. You have that f<span>our times a number minus twice another number is -8:
</span>
4x-2y=-8
3. And t<span>he sum of the two number is 19:
</span>
x+y=19
4. As you can see, you have two equations:
4x-2y=-8 (i)
x+y=19 (ii)
5. Let's clear the "x" from the equation (ii):
x=19-y
6. Now, you need to susbtitute x=19-y into the equation (i):
4x-2y=-8
4(19-y)-2y=-8
76-4y-2y=-8
76-6y=-8
-6y=-8-76
-6y=-84
y=-84/-6
y=14
7. You must susbstitute y=14 into the equation (ii) and clear "x":
x+y=19
x+14=19
x=19-14
x=5
The answer is: 5 and 14
Answer:
= -223
Step-by-step explanation:
hope this will help u mate :)
#shadow
