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2 years ago

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Which system of linear inequalities is represented by the graph?

1 answer:

jeka57 [31]2 years ago

6 0

First line....solid line...means there is an equal sign in the problem....it has a y int of (0,2)....it has a slope of -1/3....and it is shaded below the line...the inequality for this line is : y < = - 1/3x + 2 <== this is one of them

2nd line...dashed line...means there is no equal sign....it has a y int of (0,3)...it has a slope of 2/3...and it is shaded above the line...so the inequality for this line is : y > 2/3x + 3 <== this is ur other inequality

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To solve the inequality m/-7<(or equal to) 14 , what should be done to both sides?

Marizza181 [45]

Answer:

$\large\boxed{m\geq-98}$

Step-by-step explanation:

$\dfrac{m}{-7}\leq14\\\\-\dfrac{m}{7}\leq14\qquad\text{change the signs}\\\\\dfrac{m}{7}\geq-14\qquad\text{multiply both sides by 7}\\\\7\!\!\!\!\diagup^1\cdot\dfrac{m}{7\!\!\!\!\diagup_1}\geq(7)(-14)\\\\m\geq-98$

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2 years ago

Read 2 more answers

Find an equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4

Alina [70]

equation for the perpendicular Bisector of the line segment whose endpoints are (-9,-8) and (7,-4)

Perpendicular bisector lies at the midpoint of a line

Lets find mid point of (-9,-8) and (7,-4)

midpoint formula is

$\frac{x_1+x_2}{2} ,\frac{y_1+y_2}{2}$

$\frac{-9+7}{2} ,\frac{-8+-4}{2}$

midpoint is (-1, -6)

Now find the slope of the given line

(-9,-8) and (7,-4)

$slope = \frac{y2-y1}{x2-x1} = \frac{-4-(-8)}{7-(-9)}$

$slope = \frac{-4+8}{7+9}= \frac{4}{16} =\frac{1}{4}$

Slope of perpendicular line is negative reciprocal of slope of given line

So slope of perpendicular line is -4

slope = -4 and midpoint is (-1,-6)

y - y1 = m(x-x1)

y - (-6) = -4(x-(-1))

y + 6 = -4(x+1)

y + 6 = -4x -4

Subtract 6 on both sides

y = -4x -4-6

y= -4x -10

equation for the perpendicular Bisector y = -4x - 10

3 0

2 years ago

Please answer see the image

mash [69]

Answer:

<h2>67.7</h2><h2 />

Step-by-step explanation:

perimeter = semicircle (x2) + parallelogram side (x2)

= 1/2 π 12 (x2) + 15 (x2)

= 37.7 + 30

= 67.7

8 0

2 years ago

Anybody can help?????

Vikentia [17]

The formula of an area of a circle:

$A=\pi r^2$

r - a radius

We have r = 14m. Substitute:

$A=\pi\cdot14^2=196\pi\ m^2$

If you want an approximate area, you can accept $\pi\approx3.14$

Then:

$A\approx196\cdot3.14=615.44\ m^2$

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2 years ago

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Charra [1.4K]

How is this a question did you re word it

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2 years ago