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Reil [10]
3 years ago
14

Which of the following equations defines a line that is parallel to the line y=-4/3x-4 and passes through the point (3,-1)

Mathematics
2 answers:
leonid [27]3 years ago
7 0

Answer:

<h2>D.</h2>

Step-by-step explanation:

The given line is

y=-\frac{4}{3}x-4

Now, if the new line is parallel to the given one, that means it must have the same slope.

m=-\frac{4}{3}

We also know that the new line passes through point (3,-1).

Then, we use the point-slope formula to find the equation of the new line:

y-y_{1} =m(x-x_{1} )\\y-(-1)=-\frac{4}{3}(x-3)\\ y=-\frac{4}{3}x+4-1\\ y=-\frac{4}{3}x+3

Therefore, the line that passes through (3,-1) and it's parallel to the given line is: y=-\frac{4}{3}x+3.

The image attached show these parallel lines.

ValentinkaMS [17]3 years ago
5 0

Answer:

d

Step-by-step explanation:

given that your slop is -4/3, plug the (x,y) point in to the equation of y = -4x/3 +b

-1 = -4 + b , b = 3

y = -4x/3 + 3

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