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Sphinxa [80]
3 years ago
11

Shawn is buying a new Jet Ski

Mathematics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

Step-by-step explanation:

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(13,12)

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A system of identifying call letters uses call letters that begin either with E or W. Some have a total of 2 letters, and others
Klio2033 [76]

Answer:

If repetition is allowed then the different call letters possible are 1404.

If repetition is allowed then the different call letters possible are 1250.

Step-by-step explanation:

The call letter are of either 2 letter or 3 letters.

And for them to be identified they should start with either E or W.

  • If Repetition is allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 26 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place and third place can be filled with any of the 26 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place and third place can be filled with any of the 26 letters.

Total number of possible letters: 26 + 26 + (26)² + (26)² = 1404

Thus, if repetition is allowed then the different call letters possible are 1404.

  • If Repetition is not allowed:

Consider the call letters with 2 letter:

Possible number of call letters starting with E : <u>E</u> _

The second place can be filled any of the 25 letters.

Possible number of call letters starting with W : <u>W</u> _

The second place can be filled any of the 25 letters.

Consider the call letters with 3 letter:

Possible number of call letters starting with E : <u>E</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Possible number of call letters starting with W : <u>W</u> _ _

The second place can be filled with any of the remaining 25 letters and the third can be filled with the remaining 24 letters.

Total number of possible letters: 25 + 25+ (25 × 24) + (26 × 24) = 1250

Thus, if repetition is allowed then the different call letters possible are 1250.

5 0
3 years ago
3
katovenus [111]

Question is Incomplete, Complete question is given below.

Mr. Jablonski's class is making fudge for a bake sale. Mr. Jablonski

has a recipe that makes 3/4 pound of fudge. There are 21 students in

the class. Each student uses the recipe to make one batch of fudge.

How many pounds of fudge do the students make?

Answer:

student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

Step-by-step explanation:

Given:

Mr. Jablonski  recipe makes 3/4 pound of fudge.

Number of student in class = 21 students.

Each student uses the recipe to make one batch of fudge.

Hence to calculate Total amount of fudge student made we will multiply the amount of fudge used in recipe with Number of students.

Total amount of fudge student made = amount of fudge used in recipe × Number of students.

Total amount of fudge student made = \frac{3}{4}\times21 = \frac{63}{4} \ lbs =15 \frac{3}{4}\ lbs = 15.75\ lbs

Hence the student made \frac{63}{4} \ lbs \ OR \ 15 \frac{3}{4}\ lbs \ OR \ 15.75\ lbs of fudge.

8 0
3 years ago
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