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Papessa [141]
3 years ago
8

Counter-controlled repetition is also known as:

Computers and Technology
1 answer:
const2013 [10]3 years ago
3 0

Answer:

a) definite repetition

Explanation:

The counter-controlled repetitions is one in which we know the number of times a loop will be followed or performed.

Definite repetition is the one in which we know the number of iterations to be performed by a loop before the execution of the loop.  

For Example:  

Repeat a loop for 25 times printing out b *.

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Ilya [14]

Answer:

umm, we can't say any links

Explanation:

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Which magazine introduced the first microcomputer kit for the mits altair in its january 1975 issue?
Tcecarenko [31]

Answer:

Popular Electronics  is the correct answer.

Explanation:

It is the first magazine that released in the year 1975, Jan. The following magazine is about the initial microcomputer kit which for the Mits Altair.

So, that's why the following answer is not false because it is the first magazine that released the article about the following microcomputer kit that is update on the cover of the magazine.

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3 years ago
Write c++ program to find maximum number for three variables using statement ?​
pantera1 [17]

Answer:

#include<iostream>

using namespace std;

int main(){

int n1, n2, n3;

cout<<"Enter any three numbers: ";

cin>>n1>>n2>>n3;

if(n1>=n2 && n1>=n3){

cout<<n1<<" is the maximum";}

else if(n2>=n1 && n2>=n3){

cout<<n2<<" is the maximum";}

else{

cout<<n3<<" is the maximum";}

return 0;

}

Explanation:

The program is written in C++ and to write this program, I assumed the three variables are integers. You can change from integer to double or float, if you wish.

This line declares n1, n2 and n3 as integers

int n1, n2, n3;

This line prompts user for three numbers

cout<<"Enter any three numbers: ";

This line gets user input for the three numbers

cin>>n1>>n2>>n3;

This if condition checks if n1 is the maximum and prints n1 as the maximum, if true

<em>if(n1>=n2 && n1>=n3){</em>

<em>cout<<n1<<" is the maximum";}</em>

This else if condition checks if n2 is the maximum and prints n2 as the maximum, if true

<em>else if(n2>=n1 && n2>=n3){</em>

<em>cout<<n2<<" is the maximum";}</em>

If the above conditions are false, then n3 is the maximum and this condition prints n3 as the maximum

<em>else{</em>

<em>cout<<n3<<" is the maximum";}</em>

return 0;

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3 years ago
When hundreds, thousands, or even hundreds of thousands of zombie computers are gathered into a logical computer network under t
Ainat [17]
Virus such as a Trojan or Worm, and can cause network crashes.
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3 years ago
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Given two 2x3 (2 rows, 3 columns) arrays of integer , x1 and x2, both already initialized , two integer variables , i and j, and
Gnesinka [82]
JAVA programming was employed...

What we have so far:
* Two 2x3 (2 rows and 3 columns) arrays. x1[i][j] (first 2x3 array) and x2[i][j] (second 2x3 array) .
* Let i = row and j = coulumn.
* A boolean vaiable, x1rules

Solution:

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x1[i][j] = num.nextInt();
   }
}// End of Array 1, x1.

for(int i=0; i<2; i++)
{
   for(int j=0; j<3; j++)
   {
      x2[i][j] = num.nextInt();
   }
}//End of Array 2, x2
This should check if all the elements in x1 is greater than x2:

x1rules = false;
if(x1[0][0]>x2[0][0] && x1[0][1]>x2[0][1] && x1[0][2]>x2[0][2] && x1[1][0]>x2[1][0] && x1[1][1]>x2[1][1] && x1[1][2]>x2[1][2])
{
   x1rules = true;
   system.out.print(x1rules);
}
else
{
   system.out.print(x1rules);
}//Conditional Statement
7 0
3 years ago
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