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attashe74 [19]
3 years ago
10

An ______ search is when the buyer looks for information beyond personal knowledge to help make the buying decision, such as che

cking the Internet, asking a friend, or visiting a showroom.
Computers and Technology
1 answer:
victus00 [196]3 years ago
6 0

Answer: External

Explanation: External search could be explained as the additional information gathered beyond an individual's personal knowledge or experience in a bit to influence the individual's decision on a particular product or topic. This additional information could include; information sought from friends and families, online or internet research on relevant site, blogs or publications.

Therefore, a buyer who asks a friend, checking the internet or visiting a showroom or make other enquiries beyond his personal knowledge in other to make buying decision is making an external search.

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What portable computing devices, designed for user convenience, have a sensor called an accelerometer that senses vibrations and
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A testing lab wishes to test two experimental brans of outdoor pain long each wiil last befor fading . The testing lab makes six
Simora [160]

Answer:

The answer is "\bold{Brand \ A \ (35, 350, 18.7) \ \ Brand \ B \ (35, 50, 7.07)}"

Explanation:

Calculating the mean for brand A:

\to \bar{X_{A}}=\frac{10+60+50+30+40+20}{6}  =\frac{210}{6}=35

Calculating the Variance for brand A:

\sigma_{A}^{2}=\frac{\left ( 10-35 \right )^{2}+\left ( 60-35 \right )^{2}+\left ( 50-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 20-35 \right )^{2}}{5} \\\\

     =\frac{\left ( -25 \right )^{2}+\left ( 25  \right )^{2}+\left ( 15\right )^{2}+\left ( -5 \right )^{2}+\left ( 5 \right )^{2}+\left ( 15 \right )^{2}}{5} \\\\ =\frac{625+ 625+225+25+25+225}{5} \\\\ =\frac{1750}{50}\\\\=350

Calculating the Standard deviation:

\sigma _{A}=\sqrt{\sigma _{A}^{2}}=18.7

Calculating the Mean for brand B:

\bar{X_{B}}=\frac{35+45+30+35+40+25}{6}=\frac{210}{6}=35

Calculating the Variance for brand B:

\sigma_{B} ^{2}=\frac{\left ( 35-35 \right )^{2}+\left ( 45-35 \right )^{2}+\left ( 30-35 \right )^{2}+\left ( 35-35 \right )^{2}+\left ( 40-35 \right )^{2}+\left ( 25-35 \right )^{2}}{5}

    =\frac{\left ( 0 \right )^{2}+\left ( 10 \right )^{2}+\left ( -5 \right )^{2}+\left (0 \right )^{2}+\left ( 5 \right )^{2}+\left ( -10 \right )^{2}}{5}\\\\=\frac{0+100+25+0+25+100}{5}\\\\=\frac{100+25+25+100}{5}\\\\=\frac{250}{5}\\\\=50

 Calculating the Standard deviation:  

\sigma _{B}=\sqrt{\sigma _{B}^{2}}=7.07

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A disk with many program and data files scattered on it is said to be ____.
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