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4 years ago

Find the equivalent expression to 5^6 5^11/5^5 5^6/5^1 5^1/5^16 5^11/5^-5

Mathematics

1 answer:

pashok25 [27]4 years ago

3 0

Answer:

$5^{11}/5^5$

Step-by-step explanation:

$5^{11}/5^5=5^6$

$5^6/5^1=5^5$

$5^1/5^{16}=5^{-15}$

$5^{11}/5^{-5}=5^{16}$

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1. The spinner shown has six congruent sections.

kondaur [170]

Answer:

Step-by-step explanation:

The probability of obtaining a 3 is

P(3) = $\frac{1}{6}$

Then after 30 spins the predicted number of times it should land on 3 is

30 × $\frac{1}{6}$ = 5

8 0

2 years ago

We are going to fence in a rectangular field that encloses 75 ft2. Determine the dimensions of the field that will require the l

pychu [463]

Answer:

For width W and length L, we have:

W = L = √(75ft^2) = 8.66ft

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = L*W

and the perimeter is:

P = 2*L + 2*W

First, we know that the area of our rectangle is:

A = 75ft^2 = L*W

And we want to minimize the perimeter of our rectangle, then we need to minimize:

P = 2*L + 2*W

From the equation:

75ft^2 = L*W

We can isolate one of the variables, let's isolate L

L = (75ft^2)/W

We could replace this in the perimeter equation:

P(W) = 2*( (75ft^2)/W) + 2*W

P(W) = (150 ft^2)/W + 2*W

To find the minimum of the perimeter we need to look at the zero of the first derivative of P(W).

P'(W) = dP(W)/dW = -(150ft^2)/W^2 + 2

Now we need to find the value of W such that:

P'(W) = 0

0 = -(150ft^2)/W^2 + 2

(150 ft^2)/W^2 = 2

(150ft^2) = 2*W^2

(150ft^2)/2 = W^2

75 ft^2 = W^2

√(75ft^2) = W = 8.66ft

And remember that:

L = (75ft^2)/W

replacing with W = √(75ft^2)

L = (75ft^2)/√(75ft^2) = √(75ft^2)

Then:

W = L = √(75ft^2) = 8.66ft

6 0

3 years ago

I Need Help PLease!

RUDIKE [14]

Answer:

$\sqrt {72} = 6\sqrt 2$

Step-by-step explanation:

Ashton estimates the square root of 72 in the following way:

√72=

2√36=

2×6=12

a) Explain why his reasoning is incorrect

This is incorrect because $\sqrt2 * 6$ is the correct answer but he has missed the square root term on 2.

$=\sqrt {2^2X2X3^2 }$

$=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }$

$=2 X \sqrt 2 X 3$

$= \sqrt 2 X 6$

or can be written as:

$= 6\sqrt 2$

b) Estimate the square root of 72 to the nearest tenth without using your calculator. Show your work.

Find the factors of 72 we get $\sqrt {2X2X2X3X3 }$

Now, we will combine 2 terms if the are same so,

$=\sqrt {2^2X2X3^2 }$

$=\sqrt {2^2} \sqrt 2 \sqrt {3^2 }$

$=2 X \sqrt 2 X 3$

$= \sqrt 2 X 6$

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$\sqrt {72} = 6\sqrt 2$

4 0

3 years ago

What value of x makes this equation true?

Rus_ich [418]

Answer:

B. -44

Step-by-step explanation:

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first subtract 0.3x to the other side of 0.8x which will equal

-7=0.5x+15

Then subtract 15 to the othe side of the equal sign which will be

-22=0.5x

Then divide both sides of 0.5( use calculator and put in -22/0.5)

which will be -44

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3 years ago

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slavikrds [6]

Answer:

Step-by-step explanation:

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3 years ago