Answer:
The product owner is one of the technical scrum roles. The owner of the product (product owner) is the one who makes the customer's decisions. Your responsibility is the value of the product. In order to simplify communication and decision-making, it is necessary that this role falls to a single person.g
Explanation:
For the project to have a chance of success, the entire organization must respect the decisions of the Product Owner. No one, not even the CEO, should allow such decisions to be invalidated, and no one should tell the development team what to develop and deliver, except for the Product Owner, who establishes and orders the elements of the Product Backlog. The Product Owner's decisions may be influenced by others, but it is he who will have the last word.
<u>The Product Owner may delegate part of his responsibilities (such as preparing the list of items in the Product Backlog to the development team), but it will remain his responsibility.</u>
Answer : Monitor may be in sleep/hibernate mode.
Answer:Human beings, plants, animals and birds are living things.
Explanation:Living things are highly organized, meaning they contain specialized, coordinated parts. All living organisms are made up of one or more cells, which are considered the fundamental units of life. ... Multicellular organisms—such as humans—are made up of many cells.
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LET StatementIt is used to assign the value to a variable. LET is an optional statement i.e. without using LET statement one can assign the value to a variable. The data type must match with the variable type otherwise type mismatch error will occur.Most programming languages have a data type called a string, which is used for data values that are made up of ordered sequences of characters, such as "hello world". A string can contain any sequence of characters, visible or invisible, and characters may be repeated.A string can be a constant or variable .
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#include <iostream>
using namespace std;
int main() {
string input;
string rand_type;
int number=rand()%100+1; //number between 1 and 100
if ( number % 2 == 0)
rand_type= "even";
else
rand_type="odd";
cout << "your guess: ";
cin >> input;
if ( input== rand_type)
cout << "correct.\n";
else
cout << "incorrect.\n";
return 0;
}