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castortr0y [4]
2 years ago
13

The people, procedures, hardware, software, data, and knowledge needed to develop computer systems and machines that can simulat

e human intelligence process include _____________, _______________, and _______________.
Computers and Technology
1 answer:
Natalka [10]2 years ago
3 0

The people, procedures, etc. needed to create computer systems that can simulate human intelligence process include learning, reasoning, and self-correction .

<h3>What is artificial intelligence system?</h3>

This is known to be a type of system that is made use of people, procedures, hardware, software, etc. to create a type of computer systems and machines.

Conclusively, Know that they  often influence human intelligence processes, by  in the area of learning (the getting of information and methods for using the information), reasoning (thorough the use of laws or rules to come to a conclusion), and self-correction (through the use of different occurrences or outcome from one event to boast its performance on future times).

Learn more about  human intelligence from

brainly.com/question/9786721

You might be interested in
Software is the brain of computer. Explain this starement
Annette [7]

here you go

i hope this helps you

5 0
3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
2 years ago
A government agency is getting rid of older workstations. The agency will donate these workstations, along with other excess com
algol [13]

The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.

<h3>What is a hard disc?</h3>

The "DoD Standard" is a term used during the data sanitizing industry and refers to DoD 5220.22-M, and the further discussion can be defined as follows:

The simplest ways are being used to help eliminate the previously stored data, by deleting hard disc storage facilities with the same data wherever that used a sequence of all zeros.

The sparging eliminates statistics to entirely delete the gravitational flux from electronic media.

Hard drives as well as other data storage devices, for example, computer tapes, retain magnetic data.

It could no longer be seen as storage after a disk is degaussed.

Therefore, the final answer is "Using the DoD 5220.22-M method and  Degauss media with a magnet".

Learn more about hard disc at:

brainly.com/question/13329582

#SPJ1

3 0
2 years ago
Common separators or delimiters used when converting a table to text include _______________________ , paragraph marks, or comma
Anon25 [30]

Answer:

tabs.

Explanation:

Microsoft Word refers to a word processing software application or program developed by Microsoft Inc. to enable its users to type, format and save text-based documents.

In Microsoft Word 2019, the users are availed with the ability to edit the word document in the following view type;

I. View Mode.

II. Print Mode.

III. Drift Layout.

To easily and quickly convert text to tables in Microsoft Word, you should insert common separators between the text columns. The common separators or delimiters used when converting a table to text include tabs, paragraph marks, or commas.

Tabs or commas are used to indicate where the texts are divided into table columns while paragraph marks indicate where a new table row begins.

6 0
3 years ago
If a user's input string matches a known text message abbreviation, output the unabbreviated form, else output: Unknown. Support
Molodets [167]

Answer:

Here is the JAVA program. I  have added a few more abbreviations apart from LOL and IDK.

import java.util.Scanner; // to take input from user

public class MessageAbbreviation {

public static void main(String[] args) { //start of main() function body

   Scanner input = new Scanner(System.in); // create object of Scanner

       String abbreviation= ""; //stores the text message abbreviation

/* In the following lines the abbreviation string type variables contain the un-abbreviated forms */

           String LOL = "laughing out loud";

           String IDK = "i don't know";

           String BFF = "best friends forever";

           String IMHO = "in my humble opinion";

           String TMI = "too much information";

           String TYT = "take your time";

           String IDC = "I don't care";

           String FYI = "for your information";

           String BTW = "by the way";

           String OMG = "oh my God";

//prompts the user to enter an abbreviation for example LOL

           System.out.println("Input an abbreviation:" + " ");

           if(input.hasNext()) { // reads the abbreviation form the user

           abbreviation= input.next(); }

// scans and reads the abbreviation from user in the abbreviation variable

/*switch statement checks the input abbreviation with the cases and prints the un abbreviated form in output accordingly. */

    switch(abbreviation) {

       case "LOL" : System.out.println(LOL);

                    break;

       case "IDK" : System.out.println(IDK);

                    break;

       case "BFF" : System.out.println(BFF);

                    break;

       case "IMHO": System.out.println(IMHO);

                     break;

       case "TMI": System.out.println(TMI);

                     break;

       case "TYT": System.out.println(TYT);

                     break;

       case "IDC": System.out.println(IDC);

                     break;

       case "FYI": System.out.println(FYI);

                     break;

       case "BTW": System.out.println(BTW);

                     break;

       case "OMG": System.out.println(OMG);

                     break;

                     

       default    : System.out.println("Unknown"); } } }

Explanation:

The program first prompts the user to enter an abbreviation. Lets say the user enters LOL. Now the switch statement has some cases which are the conditions that are checked against the input abbreviation. For example if the user enters LOL then the following statement is executed:

case "LOL" : System.out.println(LOL);

This means if the case is LOL then the message ( un abbreviated form) stored in the LOL variable is displayed on output screen So the output is laughing out loud.

Anything else entered other than the given abbreviations will display the message: Unknown

The output is attached as screen shot.

5 0
3 years ago
Read 2 more answers
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