Yes it will, they are the same value just in diff locations
1) At 95% Confidence interval the critical value is z0.025= 1.96 Margin of error = 0.02 Or, z0.025* sqrt(p(1 - p)/n) = 0.02 Or, 1.96 * sqr
Answer:
19
Step-by-step explanation:
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
..
.
.
.
.
.
.
.
.
..
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
..
.
.
.
.
.
.
..
.
.
.
..
.
.
.
.
.
..
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
.
21
We have 4 deliveries ( 12 1/3 , 8 3/4, 17 2/8 and 23 2/3 miles ) and also the final delivery : 10 5/10 miles = 10 1/2 miles.
We have to add up all the deliveries and to divide the result by 5:
( 12 1/3 + 8 3/4 + 17 1/4 + 23 2/3 + 10 1/2 ) : 5 =
= 72 1/2 : 5 = 72.5 : 5 = 14.5 = 14 1/2
Answer: The average distance for all segments of this trip is 14 1/2 miles.