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nika2105 [10]
3 years ago
8

Please help will mark as brainliest

Mathematics
1 answer:
BartSMP [9]3 years ago
5 0

Answer:

40

Step-by-step explanation:

3x + 7 = 5x - 15

2x = 22

x = 11

QC = 51 - x = 51 - 11 = 40

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At the start of the month, the value of an investment was $73.42. By the end of the month, the value of the investment changed b
Aleonysh [2.5K]

Answer:

0.8%.

Step-by-step explanation:

Given:

At the start of the month, the value of an investment was $73.42.

By the end of the month, the value of the investment changed by a loss of $13.53.

Question asked:

What was the value, in dollars, of the investment at the end of the month?

What was the percent loss?

Solution:

At the start of the month, the value of an investment = $73.42.

Loss = $13.53.

<u><em>The value, of the investment at the end of the month = The value of an investment at the start of the month - loss</em></u>

The value, of the investment at the end of the month = $73.42 - $13.53

                                                                                         = $59.89

Thus, the value, of the investment at the end of the month is $59.89.

Now, we will find percent loss:-

Percent\ loss = \frac{Loss}{value\ of \ investment\ at \ start}

                    =\frac{59.89}{73.42} \\=0.81\%

Thus, percent loss on investment by the end of the month is 0.8%.

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The slope intercept IS y=2/5x+7
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