The area enclosed by the figure is 4533.48 square meters.
<u>Step-by-step explanation:</u>
Side length of the square = 42m
The semicircle is attached to each side of the square. So the diameter of the semicircle is the length of the square.
Radius of the semicircle = 21m
Area of the square = 42 x 42 = 1764 square meters
Area of 1 semicircle = π(21 x 21) /2
= (3.14) (441) /2
= 1384.74/2
= 692.37 square meters
Area of 4 semicircle = 4 x 692.37
= 2769.48 square meters
Total area = 1764 + 2769.48
= 4533.48 square meters
The area enclosed by the figure is 4533.48 square meters.
Assuming a d-heap means the order of the tree representing the heap is d.
Most of the computer applications use binary trees, so they are 2-heaps.
A heap is a complete tree where each level is filled (complete) except the last one (leaves) which may or may not be filled.
The height of the heap is the number of levels. Hence the height of a binary tree is Ceiling(log_2(n)), for example, for 48 elements, log_2(48)=5.58.
Ceiling(5.58)=6. Thus a binary tree of 6 levels contains from 2^5+1=33 to 2^6=64 elements, and 48 is one of the possibilities. So the height of a binary-heap with 48 elements is 6.
Similarly, for a d-heap, the height is ceiling(log_d(n)).
Answer:
There are 40 problems on the test
Step-by-step explanation:
Let p = the number of problems on the test
The number of problems on the test times the percent correct is the number correct
p * 85% = 34
p * .85 = 34
Divide each side by .85
p * .85/.85 = 34/.85
p = 40
There are 40 problems on the test
Answer:
it'll take her 36 months
Step-by-step explanation:
i just plugged in random numbers into the calculator-_-
9/26 is the correct answer
