Given that the two swimmers competed and Ursula's speed is 60 m/min while Andre's speed is 48 m/min. The distance that the Ursula will catch up with Andre will be:
distance=(relative speed)×(time)
relative speed=60-48=12 m/min
the two swimmers met at a distance of:
12×1
=12 meters
What is the question? If you are only trying to expand the
expression then the answer would be:
1/4 (5y-3)+ 1/16 (12y+17)
(5y/4) – (3/4) + (12y/16) + (17/16)
1.25y – 0.75 + 0.75y + 1.0625
2y + 0.3125
If you are trying to find for y, then you forgot to equate
it to 0, that is:
2y + 0.3125 = 0
2y = -0.3125
<span>y = 0.15625</span>
Let's first denote:
F - a favorable response
F' - an unfavorable response
S - successful
We know that:
So, from the conditional probability, we can calculate:
Answer E.
I feel like it would be 5/12, but im not 100% sure
Its a squared + xb squared = c squared so its 11 squared + 11 squared equals c squared. So I'm gonna take it down to the next step and say 11x11+ 11x11= c squared, then you end up with 121+121= c squared then you add those two and end up with 242= c squared, so then you find the square root of 242 so you should end up with 15.5 and the number goes on and on and on
