Answer:
Step-by-step explanation:
65%
Step-by-step explanation:
Given: Full capacity= 200000 litres
Amount of fuel used during flight= 130000 litres
Now, finding percentage of fuel used on the flight.
∴ Percentage of fuel used=
Solving it, we will get
∴ 65% of fuel capacity been used in this flight.
Answer:
It make 6 circles in a minute.
Step-by-step explanation:
Given:
a ball travels in a complete circle every 10 seconds
i.e
one complete circle = time taken 10 seconds.
Two complete circle = time taken 20 seconds.
Three complete circle = time taken 30 seconds.
Four complete circle = time taken 40 seconds.
Five complete circle = time taken 50 seconds.
Six complete circle = time taken 60 seconds.
60 seconds = one minute.
∴ Six complete circle in one minute.
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value ![C(0)= $16,000](https://tex.z-dn.net/?f=C%280%29%3D%20%2416%2C000)
Depreciation rate is ![r=\frac{4.5}{100}](https://tex.z-dn.net/?f=r%3D%5Cfrac%7B4.5%7D%7B100%7D)
<h3>∴ r=0.045</h3>
Period , t=5 years
![C(t)=C(0)(1-r)^t](https://tex.z-dn.net/?f=C%28t%29%3DC%280%29%281-r%29%5Et)
Substitute the values we get
![C(5)=16000(1-0.045)^5](https://tex.z-dn.net/?f=C%285%29%3D16000%281-0.045%29%5E5)
![=16000(0.955)^5](https://tex.z-dn.net/?f=%3D16000%280.955%29%5E5)
![=16000(0.7943)](https://tex.z-dn.net/?f=%3D16000%280.7943%29)
∴ ![C(5)=12708.8](https://tex.z-dn.net/?f=C%285%29%3D12708.8)
<h3>The value C(t) of the car after 5 years is $
12709</h3>
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.