Someone please help me with the problem. it’s due tomorrow and idk what i’m doing

Mathematics

1 answer:

Hatshy [7]3 years ago

5 0

For the first question:Using the distance=rate x time formula (d=rt). Your equation would be y=38x. The 38 comes from the kathryn’s speed(rate).

For the second question: because you know the distance is now 53 substitute 53 for y and solve. 53=38x. Where x represents her time. She travels the 53 miles at a rate of 38mi/h (53 divided by 38) and solve in terms of hours 1.3947or rounded to the nearest tenth 1.4 which in terms of hours is 1 hour 24 minutes.

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Y-12=28
Y=40 here you go

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Which graph represents the parent function of y=x^2 −5?

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y=x^2-5
this can be written as:
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writing in vertex form we get:
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Divid 15 into two parts such that the sum of their reciprocal is 3/10

Klio2033 [76]

From the information obtained from the question, two equations can be created:

Let x and z be the two numbers (parts)

$\frac{1}{z} + \frac{1}{x} = \frac{3}{10}$ . . . . (1)

$z + x = 15$ . . . . (2)

By transposing (2), make 'z' the subject of the equation
$z = 15 - x$ . . . . (3)

By substituting (3) into equation (1) to find a value for x
$\frac{1}{(15 - x)} + \frac{1}{x} = \frac{3}{10}$

$\frac{15}{( 15 - x ) ( x )} = \frac{3}{10}$

$3 ( - x^{2} + 15 x ) = 150$

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∴ either $( x - 5) = 0$ OR $( x - 10 ) = 0$

Thus x = 5 or x = 10

By substituting the values of x into (2) to find z

z + (5) = 15 OR z + (10) = 15

⇒ z = 10 OR z = 5

So, the two numbers or two parts into which fifteen is divided to yield the desired results are 5 and 10.

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