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MArishka [77]
3 years ago
10

Simplify: (−2a2b) • (4a5b2) −8a7b3 −8a10b2 −8(ab)10 16a7b3

Mathematics
2 answers:
7nadin3 [17]3 years ago
7 0
I hope this helps you



-2a^2b.4.a^5.b^2



-8.(a^2+5)(b^1+2)



-8.a^7.b^3
yanalaym [24]3 years ago
6 0

Answer:

The correct option is A) -8a^{7}b^{3}.

Step-by-step explanation:

Consider the provided expression.

(-2a^2b) \cdot (4a^5b^2)

Now open the parentheses.

(-2\times4)(a^2\times a^5)(b\times b^2)

Now, use the product rule: a^m \cdot a^n= a^{m+n}

(-8)(a^{2+5})(b^{1+2})

(-8)(a^{7})(b^{3})

-8a^{7}b^{3}

Hence the simplified form of the provided expression is -8a^{7}b^{3}.

Therefore, the correct option is A) -8a^{7}b^{3}.

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m > 7

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Law Incorporation [45]

Answer:

a. 0.689

b. 0.8

c. 0.427

Step-by-step explanation:

The given scenario indicates hyper-geometric experiment because because successive trials are dependent and probability of success changes on each trial.

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

where N=4+3+3=10

n=2

k=4

a.

P(X>0)=1-P(X=0)

The probability mass function for hyper-geometric distribution is

P(X=x)=kCx(N-k)C(n-x)/NCn

P(X=0)=4C0(6C2)/10C2=15/45=0.311

P(X>0)=1-P(X=0)=1-0.311=0.689

P(X>0)=0.689

b.

The mean of hyper-geometric distribution is

μx=nk/N

μx=2*4/10=8/10=0.8

c.

The variance of hyper-geometric distribution is

σx²=nk(N-k).(N-n)/N²(N-1)

σx²=2*4(10-4).(10-2)/10²*9

σx²=8*6*8/900=384/900=0.427

6 0
3 years ago
F(x) = 6x^2 find the inverse
anygoal [31]

Answer:

The inverse is ±sqrt(x/6)

Step-by-step explanation:

Let y = 6x^2

To find the inverse, exchange x and y and then solve for y

Exchange x and y

x = 6y^2

Solve for y

Divide each side by 6

x/6 = 6y^2 /6

x/6 = y^2

Take the square root of each side

±sqrt(x/6) = sqrt(y^2)

±sqrt(x/6) =y

The inverse is ±sqrt(x/6)

6 0
3 years ago
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