3 years ago

How many student preferred math??

Mathematics

1 answer:

stich3 [128]3 years ago

5 0

B,13 students prefered math

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The graphs of the equation y = 4x + 1 and y - kx = 10 are perpendicular when k = _______?

Ann [662]

Answer:

$k=-\frac{1}{4}$

Step-by-step explanation:

we have

Line 1

$y=4x+1$

Equation in slope intercept form

The slope is equal to

$m_1=4$

Line 2

$y-kx=10$

$y=kx+10$

Equation in slope intercept form

The slope is equal to

$m_2=k$

we know that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of the slopes is equal to -1)

$m_1*m_2=-1$

substitute

$(4)(k)=-1$

$k=-\frac{1}{4}$

3 0

3 years ago

Solve. −3 2/3x=−2 1/5 What is the solution to the equation? Enter your answer as a simplified fraction in the box. x =

Artyom0805 [142]

Answer:

i think it is: x=3/5

Step-by-step explanation:

hope it helps

8 0

2 years ago

Solve the equation using the quadratic formula. Enter each solution in simplest form.

sergeinik [125]

For this case we have the following quadratic equation:

$x ^ 2-4x + 23 = 0$

The solutions will be given by:

$x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}$

Where:

$a = 1\\b = -4\\c = 23$

Substituting the values we have:

$x = \frac {- (- 4) \pm \sqrt {(- 4) ^ 2-4 (1) (23)}} {2 (1)}\\x = \frac {4 \pm \sqrt {16-92}} {2}\\x = \frac {4 \pm \sqrt {-76}} {2}\\x = \frac {4 \pm \sqrt {76i ^ 2}} {2}\\x = \frac {4 \pmi \sqrt {76}} {2}\\x = \frac {4 \pmi \sqrt {2 ^ 2 * 19}} {2}\\x = \frac {4 \pm2i \sqrt {19}} {2}\\x = 2 \pm i\sqrt {19}$