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Sonbull [250]
4 years ago
12

The ordered pair (, 4) is a solution to the equation y=5x-1.

Mathematics
2 answers:
DIA [1.3K]4 years ago
5 0

y=5x-1

use the substitution method since y= 4

4= 5x-1

move -1 to the other side

sign changes from -1 to +1

4+1= 5x-1+1

4+1= 5x

5= 5x

divide both sides by 5 to get x by itself

5/5= 5/5x

Cross out 5 and 5, divide by 5 and then becomes 1*1*x= x

x=5/5

Answer: x= 1

(1,4)

Snezhnost [94]4 years ago
4 0
So, if you’re only given the y coordinate in your problem, you would plug that back into your equation
y=5x-1 turns into
4=5x-1 and you can solve by
5=5x
1=x
so the ordered pair turns out to be
(1,4)
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a wildlife manager determines that the function y=200x1.07* represents the deer population at a state park x years after the pop
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Answer:

Table:

0,200

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8,344

12, 450

Population after 12 years is 450 deer

Initial population is 200 deer.

Step-by-step explanation:

You take the x in the table and plug it in as an exponent so you will need a calculator or multiple the 1.07 by that many times so 1.07 12 times multipled by itself. and the initial is 0 years so anything to the exponent of 0 is 1 so that show i got 200 for the x=0

8 0
3 years ago
A box of candy hearts contains 52 hearts, of which 19 are white, 10 are tan, 7 are pink, 3 are purple, 5 are yellow, 2 are orang
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<u>Answer-</u>

a. Probability that  three of the candies are white = 0.29

b. Probability that three are white, 2 are tan, 1 is pink, 1 is yellow, and 2 are green = 0.006

<u>Solution-</u>

There are 19 white candies, out off which we have to choose 3.

The number of ways we can do the same process =

\binom{19}{3} = \frac{19!}{3!16!} = 969

As we have to draw total of 9 candies, after 3 white candies we left with 9-3 = 6, candies. And those 6 candies have to be selected from 52-19 = 33 candies, (as we are drawing candies other than white, so it is subtracted)

And this process can be done in,

\binom{33}{6} = \frac{33!}{6!27!} =1107568

So total number of selection = (969)×(1107568) = 1073233392

Drawing 9 candies out of 52 candies,

\binom{52}{9} = \frac{52!}{9!43!} = 3679075400

∴P(3 white candies) = \frac{1073233392}{3679075400} =0.29



Total number of ways of selecting 3 whites, 2 are tans, 1 is pink, 1 is yellow, and 2 are greens is,

\binom{19}{3} \binom{10}{2} \binom{7}{1} \binom{5}{1} \binom{6}{2}

=(\frac{19!}{3!16!}) (\frac{10!}{2!8!}) (\frac{7!}{1!6}) (\frac{5!}{1!4!}) (\frac{6!}{2!4!})

=(969)(45)(7)(5)(15)=22892625

Total number of selection = 3 whites + 2 are tans + 1 is pink + 1 is yellow + 2 greens = 9 candies out of 52 candies is,

\binom{52}{9}=\frac{52!}{9!43!} =3679075400

∴ P( 3 whites, 2 are tans, 1 is pink, 1 is yellow, 2 greens) =

\frac{22892625}{3679075400} = 0.006


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