If a secant and a tangent of a circle are drawn from a point outside the circle, then the product of the lengths of the secant and its external segment equals the square of the length of the tangent segment.

y² = 7(15+7)
y² = 7*22
y² = 154
y = √154
y = 12.4 ← to the nearest tenth

8 0

3 years ago

Susan drove to visit a friend. She drove 345

padilas [110]

Answer:

$Average\ Speed = 60 mi/hr$

Step-by-step explanation:

Given

$Distance = 345\ miles$

$Time = 5\ hours\ 45\ minutes$

Required

Determine the average speed

This is calculated as thus:

$Average\ Speed = \frac{Distance}{Time}$

Convert time to hour:

$Time = 5\ hours\ 45\ minutes$

$Time = 5\ hours + \frac{45}{60}\ hour$

$Time = 5\ hours + \frac{3}{4}\ hour$

$Time = \frac{20 + 3}{4}\ hours$

$Time = \frac{23}{4}\ hours$

$Time = 5.75\ hours$

$Average\ Speed = \frac{Distance}{Time}$

$Average\ Speed = \frac{345}{5.75}$

$Average\ Speed = 60 mi/hr$

7 0

3 years ago

20 POINTS and it has to be correct. This depends on if I pass or fail

valentina_108 [34]

Answer:

$(x+8)^{2}+(y-14)^{2}=19$

Step-by-step explanation:

The equation of a circle is: $(x-x_1)^{2}+(y-y_1)^{2}=r^2$ , where x_1 is the x coordinate of the center, y_1 is the y coordinate of the center, and r is the radius.

In this case, x_1 = -8, y_1 = 14, and r = 4.3589. Plugging these into the equation, we get:

$(x+8)^{2}+(y-14)^{2}=4.3589^2$

If you want, you can round 4.3589^2 to 19.

Then, the answer would be: $(x+8)^{2}+(y-14)^{2}=19$ .

Hope this helps!

7 0

3 years ago

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