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White raven [17]
3 years ago
7

WXYZ is congruent to PQRS. Find each measure of angle P

Mathematics
1 answer:
REY [17]3 years ago
3 0

P=45

How do I Know that?

<em>I added 35+100 and that equal to 180, so Then I subtracted 180-135 and that gave me 45. So P=35. Add all of them up to see if it = 180 and if it does, then your answer is correct. remeber 3 angles of a triangle =180.</em>

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Y = x - 1
romanna [79]

Answer: The correct answer is the third option, (-3,-4).

Step-by-step explanation: You plug in 2x + 2 for y, given that y = 2x + 2.

2x+2 = x - 1

x = -3

Now, you plug in -3 for x in an equation.

y = -3 - 1

y = -4.

(-3, -4)

4 0
2 years ago
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Nichole collected data from the basil plant in her garden. She recorded the day (x) and how much the plant had grow (y) in centi
WARRIOR [948]

Answer:

The answer is B. Nichole's basil plant started at 1 cm and grew 3 cm each day.

The equation is y = 3x +1

Step-by-step explanation:

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2 years ago
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Add a sign to 91455=0.2
Igoryamba
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4 0
3 years ago
PLEASE HELP!!! I need the answer and the work to go along with it.
Masja [62]
----------------------------------------------------------------------------------------------------
Check the picture attached.

the secants of the circle, BA and DC, intersect at point P, as shown.

i)
let m(P)=a

ii)
let m(CDA)=b, then the measure of ar CA is 2b, as "the measure of an inscribed angle is half the measure of the arc it intercepts"

iii)
m(DAB)= m(P)+m(CDA)= a+b, as DAB is an exterior angle of the triangle PAD.

iv)
then the measure of arc DB is 2m(DAB)=2(a+b)=2a+2b

v)
m(P)= \frac{(2a+2b)-2b}{2}= \frac{m(DB)-m(CA)}{2}

This is always true,
----------------------------------------------------------------------------------------------------

In our problem, there is a slight difference, we have 1 secant and one tangent, but it is just a special case and nothing changes.

As an exercise, we can repeat the steps of the general proof, by first joining U and T.
----------------------------------------------------------------------------------------------------

by the theorem we just proved,

m(R)=(m(TU)-m(SU))/2

30°=(100°-m(SU))/2

60°=100°-m(SU)

m(SU)=40°

5 0
3 years ago
Let (-7, 2) be a point on the terminal side of 0.
nekit [7.7K]

By applying the definitions of <em>trigonometric</em> functions, the <em>exact</em> values of the sine, secant and tangent of the point on the <em>terminal</em> side are \sin \theta = \frac{2}{\sqrt{53}}, \sec \theta = -\frac{\sqrt{53}}{7} and \tan \theta = -\frac{2}{7}.

<h3>How to determine the exact values</h3>

In this question we need to find the exact values of three <em>trigonometric</em> functions associated with the <em>terminal</em> side of an angle. The following definitions are used:

Sine

\sin \theta = \frac{y}{\sqrt{x^{2}+y^{2}}}     (1)

Secant

\sec \theta = \frac{\sqrt{x^{2}+y^{2}}}{x}     (2)

Tangent

\tan \theta = \frac{y}{x}     (3)

If we know that x = - 7 and y = 2, then the exact values of the three <em>trigonometric</em> functions:

Sine

\sin \theta = \frac{2}{\sqrt{53}}

Secant

\sec \theta = -\frac{\sqrt{53}}{7}

Tangent

\tan \theta = -\frac{2}{7}

By applying the definitions of <em>trigonometric</em> functions, the <em>exact</em> values of the sine, secant and tangent of the point on the <em>terminal</em> side are \sin \theta = \frac{2}{\sqrt{53}}, \sec \theta = -\frac{\sqrt{53}}{7} and \tan \theta = -\frac{2}{7}.

<h3>Remark</h3>

The statement reports typing errors, correct form is shown below:

<em>Let (x, y) = (- 7, 2) be a point on the terminal side of θ. Find the exact value of sin θ, sec θ and tan θ.</em>

To learn more on trigonometric functions: brainly.com/question/6904750

#SPJ1

5 0
1 year ago
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