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3 years ago

3a+1=3.6(a-2)???????

Mathematics

1 answer:

Lyrx [107]3 years ago

5 0

-10.333=A is the answer I believe

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Dont be shy give me the answer /j but help would be appreciated lol

zaharov [31]

Answer:

1.25

Step-by-step explanation:

count squares of rise and run

5 up/ 4 across = 1.25

5 0

3 years ago

Determine the term containing y^5 in the expansion of (x-3y)^8

velikii [3]

Answer:

13608x^3y^5

Step-by-step explanation:

(x-3y)^8 expanded form:

x^8 - 24x^7y + 252x^6y^2 - 1512x^5y^3 + 5670x^4y^4 - 13608x^3y^5 + .....

13608x^3y^5

4 0

3 years ago

X/x-2 + x-1/x+1= -1 Can someone walk me through the steps of this problem? Much appreciated. :)

stealth61 [152]

Answer:

x = 0 or x = 1

Step-by-step explanation:

Given equation:

$\dfrac{x}{x-2}+\dfrac{x-1}{x+1}=-1$

Multiply the two denominators to get the same denominator:

Multiply the numerator of the first fraction by the denominator of the second fraction to get the new numerator of the first fraction.

Multiply the numerator of the second fraction by the denominator of the first fraction to get the new numerator of the second fraction.

$\implies \dfrac{x(x+1)}{(x-2)(x+1)}+\dfrac{(x-2)(x-1)}{(x-2)(x+1)}=-1$

Add the numerators and keep the denominator so that there is now one fraction:

$\implies \dfrac{x(x+1)+(x-2)(x-1)}{(x-2)(x+1)}=-1$

Simplify the numerator by expanding the brackets:

$\implies \dfrac{x^2+x+x^2-3x+2}{(x-2)(x+1)}=-1$

$\implies \dfrac{2x^2-2x+2}{(x-2)(x+1)}=-1$

Simplify the denominator by expanding the brackets:

$\implies \dfrac{2x^2-2x+2}{x^2-x-2}=-1$

Multiply both sides by the denominator of the left side:

$\implies 2x^2-2x+2=-1(x^2-x-2)$

Simplify and move everything to the left side:

$\implies 2x^2-2x+2=-x^2+x+2$

$\implies 3x^2-3x=0$

Factor:

$\implies 3x(x-1)=0$

Therefore:

$\implies 3x=0 \implies x=0$

$\implies x-1=0 \implies x=1$

Therefore, x = 0 or x = 1

8 0

2 years ago

Read 2 more answers

I am a four-digit number. My first digit is a square number.

denis-greek [22]

Answer:

8493

Step-by-step explanation:

5 0

3 years ago

Please help me with this question, will mark brainliest if correct, PLEASE HURRY, no links or you'll be reported :)

Furkat [3]

Answer:

Given

ΔTQR is right
QS is altitude
ΔRSQ and ΔTSQ also right
m∠TQS = 42°, RS = 26 cm

∠RQS and ∠TQS are complementary with ∠TQS, so are 48°

∠QRS is the another one with 42°

Find QS first

26/QS = tan 48°
QS = 26 / tan 48° = 23.4

Find QT next

QS/QT = cos 42°
QT = QS / cos 42° = 23.4 / cos 42° = 31.5 (rounded)

8 0

3 years ago