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AlexFokin [52]
2 years ago
12

You wrap a wire around a piece of iron. If you slowly increase the strength of an electric current flowing through the wire, you

would expect _____.
a.the magnet to become stronger
b.the magnet to stop producing a field
c.the wire to move
d.the wire to unwrap
Mathematics
2 answers:
bearhunter [10]2 years ago
6 0
If you slowly increase the strength of an electric current flowing through the wire, you would expect the magnet to become stronger. The correct option among all the options that are given in the question is the first option or option "a". The magnetic field around the wire becomes stronger. I hope it helps you.
bixtya [17]2 years ago
3 0
The magnet to be become stronger since the set up acts as a solenoid.
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Maurice puts 130 trading cards in projector sheet he feels 7 sheets and puts the remaining four cards in an 8 sheets have the sa
cestrela7 [59]

Step-by-step explanation:

i am expecting that total cards is 234

7 0
2 years ago
I’m not sure how to do this problem
strojnjashka [21]
The first one would be x^12
6 0
3 years ago
x = c1 cos(t) + c2 sin(t) is a two-parameter family of solutions of the second-order DE x'' + x = 0. Find a solution of the seco
igomit [66]

Answer:

x=-cos(t)+2sin(t)

Step-by-step explanation:

The problem is very simple, since they give us the solution from the start. However I will show you how they came to that solution:

A differential equation of the form:

a_n y^n +a_n_-_1y^{n-1}+...+a_1y'+a_oy=0

Will have a characteristic equation of the form:

a_n r^n +a_n_-_1r^{n-1}+...+a_1r+a_o=0

Where solutions r_1,r_2...,r_n are the roots from which the general solution can be found.

For real roots the solution is given by:

y(t)=c_1e^{r_1t} +c_2e^{r_2t}

For real repeated roots the solution is given by:

y(t)=c_1e^{rt} +c_2te^{rt}

For complex roots the solution is given by:

y(t)=c_1e^{\lambda t} cos(\mu t)+c_2e^{\lambda t} sin(\mu t)

Where:

r_1_,_2=\lambda \pm \mu i

Let's find the solution for x''+x=0 using the previous information:

The characteristic equation is:

r^{2} +1=0

So, the roots are given by:

r_1_,_2=0\pm \sqrt{-1} =\pm i

Therefore, the solution is:

x(t)=c_1cos(t)+c_2sin(t)

As you can see, is the same solution provided by the problem.

Moving on, let's find the derivative of x(t) in order to find the constants c_1 and c_2:

x'(t)=-c_1sin(t)+c_2cos(t)

Evaluating the initial conditions:

x(0)=-1\\\\-1=c_1cos(0)+c_2sin(0)\\\\-1=c_1

And

x'(0)=2\\\\2=-c_1sin(0)+c_2cos(0)\\\\2=c_2

Now we have found the value of the constants, the solution of the second-order IVP is:

x=-cos(t)+2sin(t)

3 0
3 years ago
Madeline uses 58 beads to make a necklace she plans to sell 36 necklaces at each craft fair she goes to the summer she plans to
g100num [7]
<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  Multiply the number of beads per necklace by the number of necklaces:

58 x 36 = 2088

This is the number of beads needed per each craft fair.

Multiply this value by 4 to get the final value:

2088 x 4 = 8352.

She will need 8352 beads.

<h3><u>❄️</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

5 0
2 years ago
What is 92.583 rounded to the nearest tenth
miskamm [114]
92.6, you round 5 up because of the 8.
4 0
3 years ago
Read 2 more answers
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