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dedylja [7]
4 years ago
5

Can some one find the area and perimeter?? Please!!!

Mathematics
1 answer:
motikmotik4 years ago
6 0
I can but i need the question lol.
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help me ;-; this question is hard. if possible, can you try explaining how to do it too after answering? that would be blessing
Ilia_Sergeevich [38]

Answer:

$28.95

Step-by-step explanation:

Just work backwards!

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What is 75% of 8 hours and 15 minutes
jarptica [38.1K]
Approximately 6 hours and 18 minutes
8 0
3 years ago
Need help <br>problem/question in image below ​
Natasha_Volkova [10]

Answer:

Option A would be the correct answer

I don't have an explanation to type but you can trust me :)

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7 0
3 years ago
Assuming the conditions are met, if the 95% confidence interval for p was calculated to be (0.604, 0.781), what is the correct i
Ugo [173]

Answer: 95% certain that true proportion of population "p" is contained in (0.604, 0.781)

Step-by-step explanation:

We know that a 95% confidence interval is a range of values that you can be 95% sure that true mean of the population or true proportion of population lies in it .

Given : The 95% confidence interval for p was calculated to be (0.604, 0.781).

It means that we are 95% certain that true proportion of population "p" is contained in (0.604, 0.781).

Hence, the  correct interpretation for this interval :- 95% certain that true proportion of population "p" is contained in (0.604, 0.781).

3 0
3 years ago
Show all work to factor x4 − 10x2 + 9 completely.
leva [86]

Answer:

(x+1)(x-1)(x+3)(x-3)

Step-by-step explanation:

x4-10x^2+9

Group expression so that the coefficients of the x^2 terms add up to +9.

= x^4 -9x^2   - x^2+9

match coefficients in both groups

= x^4 -9x^2   - (x^2-9)

factor each group

= x^2 (x^2-9) - 1(x^2-9)

now factor out the common factor (x^2-9)

= (x^2-1)(x^2-9)

Finally, factor each quadratic factor

= (x+1)(x-1)(x+3)(x-3)

6 0
3 years ago
Read 2 more answers
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