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adell [148]
3 years ago
10

Show all work to factor x4 − 10x2 + 9 completely.

Mathematics
2 answers:
AlekseyPX3 years ago
8 0

Step-by-step explanation:

Since both terms are perfect squares, factor using the difference of squares formula, a² - b² =(a+b)(a−b)  where a=x and  b=3.

(x+3)(x-3)(x+1)(x-1)

leva [86]3 years ago
6 0

Answer:

(x+1)(x-1)(x+3)(x-3)

Step-by-step explanation:

x4-10x^2+9

Group expression so that the coefficients of the x^2 terms add up to +9.

= x^4 -9x^2   - x^2+9

match coefficients in both groups

= x^4 -9x^2   - (x^2-9)

factor each group

= x^2 (x^2-9) - 1(x^2-9)

now factor out the common factor (x^2-9)

= (x^2-1)(x^2-9)

Finally, factor each quadratic factor

= (x+1)(x-1)(x+3)(x-3)

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2 years ago
Solve for m.<br> 22m^2 + 7m - 2 = 0
pshichka [43]

Answer:

x= -1/2 and x=2/11

Step-by-step explanation:

Write the 7x as a difference. It'll make it easier to factor out. An example of this would be 11x-4x

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Look at it as if there are two equations: 22x^2+11x and -4x-2

Factor out the greatest common factor, which is 11 from the first equation. The equation will then look like this: 11x(2x+1)

Take the GCF for the second equation as well (which is -2). The equation should then also look like this: (2x+1)

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5 0
3 years ago
Given the original number n. Multiply the number by 9. Add 99. Divide this sum by 9. Subtract the original number, n, from the q
tangare [24]

Answer:

11

Step-by-step explanation:

Hello,

Given the original number n.

\large \boxed{n}

Multiply the number by 9.

\large \boxed{9n}

Add 99.

\large \boxed{9n+99}

Divide this sum by 9.

\large \boxed{\dfrac{9n+99}{9}=n+11}

Subtract the original number, n, from the quotient.

\large \boxed{n+11-n=11}

Thank you.

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Step-by-step explanation:

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Read 2 more answers
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