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tresset_1 [31]
3 years ago
14

PLEASE HURRY

Mathematics
2 answers:
snow_lady [41]3 years ago
7 0

Answer:

x = 3 ×10^2

Step-by-step explanation:

To determine how many times larger the culture sample was compared to a week earlier

We divide the values of the present sample to the past sample size

3.9 x 10^5/ 1.3 ×10^2

3.9/1.3 x10^5-3 = 3 ×10^2

Lubov Fominskaja [6]3 years ago
3 0

Answer-

the first box is 3 the second is 10 to the third then the last = 3,000

Step-by-step explanation:

just did it

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Samuel owns 270 comic books. He divided his comic books into two groups to store in boxes. The ratio of the groups appear below.
Anna71 [15]
The Answer Is 5.I Hope This Helps.
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3 years ago
Which of the following is a reflection of ( 2,4 ) across the x-axis?
fiasKO [112]

Answer:

(2,-4)

Step-by-step explanation:

(2,4) is located in Quadrent I (+,+), if you reflect over the x-axis, it would be in Quadrent IV (+,-).

if you dont understand I suggest you draw a coordinate plane on a graphing notebook.

7 0
3 years ago
What is a formula for the nth term of the given sequence?<br> 36, 24, 16...
SpyIntel [72]

Answer:

The formula to find the nth term of the given sequence is 54 · \frac{2}{3} ^{n}

Step-by-step explanation:

The formula for nth term of an geometric progression is :

a_{n} = \frac{a_{1}(r^{n})}{r}

In this example, we have a_{1} = 36 (the first term in the sequence) and

r = \frac{2}{3} (the rate in which the sequence is changing).

Knowing what the values for r and a_{1} are, now we can solve.

a_{n} = \frac{a_{1}(r^{n})}{r} = \frac{36 (\frac{2}{3} ^{n}) }{\frac{2}{3} } = 54 · \frac{2}{3} ^{n}

Therefore, the formula to find the nth term of the given sequence is

54 · \frac{2}{3} ^{n}

3 0
3 years ago
.......................look at the pic if u can......
Nataliya [291]

Answer:

A. 8x10^7 is 4000 times larger tham 2x10^4

Step-by-step explanation:


3 0
3 years ago
When f(n) = 34, what is the value of f(n-6)?
Mashutka [201]

Answer:

28

Step-by-step explanation:

f(n)=34, f(n-6)=34-6

=28

3 0
3 years ago
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