We have 2l + 2w = 120 and l/w = 2/3;
Then, l = (2/3)w;
Finally, (4/3)w + 2w = 120;
4w + 6w = 360;
10w = 360;
w = 36;
l = (2/3)x36;
l = 24;
This is the solution of the equation, where a=1, b=-5, c=7
So the discriminant is :
b^2-4ac=25-4*7= -3
The square root of -3 is non-real, this both solutions are non-real.
It would be (0,-3) and (2,3). You can see that they have a bigger distance compared to the other points being compared.
Answer:
C: The area of ABC is 1 square unit greater than the
area of ADEF
Step-by-step explanation:
Due to the area of triangle ABC and triangle DEF, the ABC triangle has dimensions that are 1 square unit greater that the area of ADEF. This is because the lines have different lengths. Good Luck on the Rest of Your Questions!!
