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8_murik_8 [283]
4 years ago
14

Drag and drop an answer to each box to correctly explain the derivation of the formula for the volume of a pyramid.

Mathematics
1 answer:
Irina18 [472]4 years ago
8 0

A prism is rectangular shaped,. a pyramid is triangular shaped.

The ratio would be  1 to 3

The formula for the pyramid is V = 1/3Bh

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1 US Dollar =13.05 pesos 1meter =1.094 yars
Evgesh-ka [11]

Answer:

$18.01

Step-by-step explanation:

Convert from pesos to US dollars

6429/13.05 = $492.64

Convert from meters to yards

1.904* 25= 27.35

Divide to find the cost of one yard of fabric

492.64/27.35 = $18.01

4 0
3 years ago
How do you do this trig problem.
loris [4]

Consider a right triangle in which one of the angles \theta satisfies

\sin\theta=\dfrac35\implies\theta=\sin^{-1}\dfrac35

That is, the side opposite \theta occurs in a ratio of 3 to 5 with the hypotenuse. The side adjacent to \theta then occurs in a ratio of 4 to 5 with the hypotenuse. In other words,

\cos\theta=\dfrac45

because

\sin^2\theta+\cos^2\theta=\dfrac9{25}+\dfrac{16}{25}=1

Then in this triangle,

\cot\theta=\cot\left(\sin^{-1}\dfrac35\right)=\dfrac{\cos\theta}{\sin\theta}=\dfrac{\frac45}{\frac35}=\dfrac43

7 0
3 years ago
For a recent project, a teacher purchased 250 pieces of red construction paper and 114 pieces of blue construction paper. What i
Lisa [10]
The answer is b because you can divide them by 2 to get the answer<span />
7 0
3 years ago
Read 2 more answers
Name the two lines and the transversal that form each pair of angles
Crank
A is a line that intersects two coplanar lines at two distinct points. The diagram shows the eight angles formed by <span>a transversal t and two lines / and m.
</span>A transversal that intersects two lines forms eight angles;Corresponding angles,Alternate exterior angles, Alternate interior angles,Consecutive exterior angles, Consecutive interior angles.

Hope it helps
3 0
3 years ago
Read 2 more answers
EXAMPLE 5 Find the maximum value of the function f(x, y, z) = x + 2y + 11z on the curve of intersection of the plane x − y + z =
Taya2010 [7]

Answer:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

<em>Maximum value of f=2.41</em>

Step-by-step explanation:

<u>Lagrange Multipliers</u>

It's a method to optimize (maximize or minimize) functions of more than one variable subject to equality restrictions.

Given a function of three variables f(x,y,z) and a restriction in the form of an equality g(x,y,z)=0, then we are interested in finding the values of x,y,z where both gradients are parallel, i.e.

\bigtriangledown  f=\lambda \bigtriangledown  g

for some scalar \lambda called the Lagrange multiplier.

For more than one restriction, say g(x,y,z)=0 and h(x,y,z)=0, the Lagrange condition is

\bigtriangledown  f=\lambda \bigtriangledown  g+\mu \bigtriangledown  h

The gradient of f is

\bigtriangledown  f=

Considering each variable as independent we have three equations right from the Lagrange condition, plus one for each restriction, to form a 5x5 system of equations in x,y,z,\lambda,\mu.

We have

f(x, y, z) = x + 2y + 11z\\g(x, y, z) = x - y + z -1=0\\h(x, y, z) = x^2 + y^2 -1= 0

Let's compute the partial derivatives

f_x=1\ ,f_y=2\ ,f_z=11\ \\g_x=1\ ,g_y=-1\ ,g_z=1\\h_x=2x\ ,h_y=2y\ ,h_z=0

The Lagrange condition leads to

1=\lambda (1)+\mu (2x)\\2=\lambda (-1)+\mu (2y)\\11=\lambda (1)+\mu (0)

Operating and simplifying

1=\lambda+2x\mu\\2=-\lambda +2y\mu \\\lambda=11

Replacing the value of \lambda in the two first equations, we get

1=11+2x\mu\\2=-11 +2y\mu

From the first equation

\displaystyle 2\mu=\frac{-10}{x}

Replacing into the second

\displaystyle 13=y\frac{-10}{x}

Or, equivalently

13x=-10y

Squaring

169x^2=100y^2

To solve, we use the restriction h

x^2 + y^2 = 1

Multiplying by 100

100x^2 + 100y^2 = 100

Replacing the above condition

100x^2 + 169x^2 = 100

Solving for x

\displaystyle x=\pm \frac{10}{\sqrt{269}}

We compute the values of y by solving

13x=-10y

\displaystyle y=-\frac{13x}{10}

For

\displaystyle x= \frac{10}{\sqrt{269}}

\displaystyle y= -\frac{13}{\sqrt{269}}

And for

\displaystyle x= -\frac{10}{\sqrt{269}}

\displaystyle y= \frac{13}{\sqrt{269}}

Finally, we get z using the other restriction

x - y + z = 1

Or:

z = 1-x+y

The first solution yields to

\displaystyle z = 1-\frac{10}{\sqrt{269}}-\frac{13}{\sqrt{269}}

\displaystyle z = \frac{-23\sqrt{269}+269}{269}

And the second solution gives us

\displaystyle z = 1+\frac{10}{\sqrt{269}}+\frac{13}{\sqrt{269}}

\displaystyle z = \frac{23\sqrt{269}+269}{269}

Complete first solution:

\displaystyle x= \frac{10}{\sqrt{269}}\\\\\displaystyle y= -\frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{-23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=-0.4

Complete second solution:

\displaystyle x= -\frac{10}{\sqrt{269}}\\\\\displaystyle y= \frac{13}{\sqrt{269}}\\\\\displaystyle z = \frac{23\sqrt{269}+269}{269}

Replacing into f, we get

f(x,y,z)=2.4

The second solution maximizes f to 2.4

5 0
3 years ago
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