All categories

4 years ago

A = (1, 3, 5, 7, 9) B= 2, 4, 6, 8, 10) C = (1.5.6.7.9) A U(BOC) =

Mathematics

1 answer:

Artemon [7]4 years ago

8 0

Answer:

$A \cup (B \cap C) = (1, 3, 5, 6, 7, 9)$

Step-by-step explanation:

Set A = (1, 3, 5, 7, 9)

Set B = (2, 4, 6, 8, 10)

Set C = (1, 5, 6, 7, 9)

We have to evaluate: A U (B O C) i.e. A union (B intersection C)

First we need to evaluate B intersection C. Remember that intersection of two sets only results in common elements of both the sets. Union of two sets result in all the elements of the two sets combined.

So,

$A \cup (B \cap C) = (1, 3, 5, 7, 9) \cup [(2, 4, 6, 8, 10) \cap (1, 5, 6, 7, 9)]\\\\ A \cup (B \cap C) = (1, 3, 5, 7, 9) \cup (6)\\\\ A \cup (B \cap C) = (1, 3, 5, 6, 7, 9)$

You might be interested in

suppose you know that over the last 10 years, the porbabiliy that your town would have at least one ma jor stor was 40%. describ

Anuta_ua [19.1K]

Answer:

The probability of a big storm is 40%.

Now, you can find a D10 (a die with 10 faces)

You can assign 4 numbers (0, 1, 2, 3) to the event "there is a major storm"

in this way, you have 40% of having a storm.

and the other 6 numbers (4, 5, 6, 7, 8, 9) to the event "there is not a major storm". This means that we have 60% of not having a storm.

now, when you roll the dice you can see if a year there will be a storm or not.

Now, you roll the dice 5 times (for the 5 years) and take note of the results and the number of storms in those 5 rolls.

Now do the same thing a bunch of times, at least 25 times.

Now, you recorded the results in each set of rolls, now see the number of sets that have at least years with storms.

Take that number and divide it by the total number of sets of data (in this case 25, for example)

The result is the probability that we are looking for.

6 0

3 years ago

Which of the following relations is a function?

MrMuchimi

Answer:

Step-by-step explanation:

<u>Definition of a Function</u>

A function is a relation between an input and an output set of values with the condition that every element in the input set relates only to one element in the output set.

From the four options presented in the question, we must select the only one that doesn't repeat the value for x and has a different value of y.

For example, the set

B. (1,4), (-5, 6), (1, 3), (-8, 2) is not a function because the input value of 1 has two different output values

C. (1,0), (-5,3), (7, 1), (-5,5) is not a function either because the input value of -5 has two different output values

The correct choice is:

A. (1,4), (-5, 2), (7, 1), (-8, 2)

6 0

3 years ago

What is the volume of the cylinder? Use 3.14 for pie and round to the answer to the nearest hundred.

Schach [20]

Answer:

502.4

Step-by-step explanation:

Volume of a cylinder(formula)=πr2h

So pie is 3.14

3.14×4×4(radius2)×10

This is equal to 502.4

Hope it helped

5 0

3 years ago

Write the slope-intercept form of the equation for the line

olga_2 [115]

Answer: y=-3/10x+1/2

Step-by-step explanation:

3 0

3 years ago

What is the solution to log2(2x^3-8)-2log2(x)=log2(x)

Charra [1.4K]

$\bf \textit{Logarithm of rationals}
\\\\
log_a\left( \frac{x}{y}\right)\implies log_a(x)-log_a(y)
\\\\\\
\textit{Logarithm of exponentials}
\\\\
log_a\left( x^b \right)\implies b\cdot log_a(x)\\\\
-------------------------------$

$\bf log_2(2x^3-8)-2log_2(x)=log_2(x)
\\\\\\
log_2(2x^3-8)-log_2(x^2)=log_2(x)\implies log_2\left( \cfrac{2x^3-8}{x^2} \right)=log_2(x)
\\\\\\
\textit{since both sides are getting }log_2\textit{ we can simply undo that}
\\\\\\
\cfrac{2x^3-8}{x^2}=x\implies 2x^3-8=x^3\implies x^3-8=0
\\\\\\
x^3=8\implies x=\sqrt[3]{8}\implies x=2$

5 0

3 years ago

Read 2 more answers